Given-
Power, P = 800W
Thickness, L = 0.6cm
Area, A = 160cm²
Thermal conductivity, k = 60W/mK
The heat conduction would be
Except 
all the values are 0.
Therefore,
Thus, the boundary conditions here would be
1. 
2. 
Answer:
1. True
2. True
3. False
Explanation:
The office location is where the soil layer is not uniform. The thickness of the soil varies which could lead to doors being jammed. The engineer needs to estimate the differential in clay soil.
The inclined surface can hold less weight than a vertical surface. The capacity to hold the weight is due to the gravitational force which is exerted to the load.
Answer:
The pressure that the container will start to leak is 154.87 psi
Explanation:
Force on end plates F = p(πR²) ⇒ pπR²
There is an equal reaction from four bolts ∴ F = pπR² / 4 .............. (1)
due to force on bolt, each bolt stretch by 
Therefore; 
.........................(2)
Leaking will start when tightening is outstretched by half turn per 16 turns per inch.
Cylinder experience a radial expansion as p increases. it is accompanied by poisson contraction 
in axial direction. That is, the bolt do not have to experience a long stretch before the pressure breaks off the plate.
...................... (3)
Axial deformation of cylinder = L times axial ∈₀
<em>see continuation in attached picture in writing to get the value of Pressure: since we have the value of P</em>
R=8", L=16", t=0.125"
Area of bolts 
V for brass = 0.3
![P = \frac{1}{8*8*16} [\frac{0.150*12.5*200*0.125*10^9}{\pi*8*125*0.125+4*0.3*0.150*200}]](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B1%7D%7B8%2A8%2A16%7D%20%5B%5Cfrac%7B0.150%2A12.5%2A200%2A0.125%2A10%5E9%7D%7B%5Cpi%2A8%2A125%2A0.125%2B4%2A0.3%2A0.150%2A200%7D%5D)
p = 1.67797.183 P ⇒ 154.87 psi
The freaking answer iis the secシ❥❥☀︎︎
Answer:
Explanation:
/* General Code for achieving perfect error for any level and any
digit of codewords*/
#include<iostream>
using namespace std;
int main(){
int level;
//Input memory levels.
cout <<" Enter number of Flash Memory levels : ";
cin>>level;
//construct array store levels.
int lvl[level];
for(int i = 0; i < level; i++){
//assign levels name
lvl[i] = i;
}
int digit;
cout << "Enter number of digit codewords :";
//Taking input of codeword digits
cin >> digit;
for(int i = 0; i < level;){
//output Codeword
cout << lvl[i];
//Skipping for n number digit codeword in level
i+=(digit+1);
}
}
/*
a) i from 0 to (i = i+(2+1))<levels
b) for length (1) -> 3 codewords
codewords -> {0,2,4}
for length (2) -> 2 codewords
codewords -> {0,3}
*/
