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brilliants [131]
3 years ago
14

2.

Physics
2 answers:
mixas84 [53]3 years ago
7 0

Answer:

Unbalanced

Explanation:

Hussein is pushing 2 N harder.

Phantasy [73]3 years ago
5 0

Answer:

Explanation:

lll

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The Moon takes about 27 days to orbit the Earth. Assuming a circular orbit, how fast is it orbiting? Express your answer in km/h
Vinvika [58]

Answer:

3727.24km/h

Explanation:

Hello!

To solve this problem we must first know what is the distance from the earth to the moon, this will be our radius.

=384400Km

Then we find the distance traveled which would be the perimeter of a circle = 2πr, finally to find the speed we divide the distance traveled by 27 days.

Finally we use conversion factor to have the speed in km / h

solving

perimeter= 2(3.14)r=2(3.14)(384400Km)=2415256.432km\\Speed=\frac{2415256.432km}{27days} *\frac{1day}{24h} =3727.24km/h

the moon is orbiting at speed of 3727.24km/h

7 0
3 years ago
If block D weighs 300 lb and block B weighs 275 lb determine the required weight of block C and the angle theta for equilibrium?
adoni [48]
Set up a free body diagram. 

<span>and by reason, Tcd = Tbd </span>

<span>Tbd y = 275 - 300*sinθ </span>
<span>Tcd y = Tc - 300*sin30 </span>

<span>Tbd x = 300*cosθ </span>
<span>Tcdx = 300 * cos30 </span>

<span>Tbd^2 = (275 - 300*sinθ)^2 + (300*cosθ)^2 </span>
<span>Tcd^2 = (300*sin30)^2 + (300 * cos30)^2 </span>

<span>(275 - 300*sinθ)^2 + (300*cosθ)^2 = (300*sin30)^2 + (300 * cos30)^2 </span>
<span>etc.</span>
5 0
3 years ago
The part of the computer that provides access to the internet is
Allisa [31]
The Modem


or physically connecting on the computer the data port is for a cable to connect
5 0
3 years ago
A merry-go-round rotates at the rate of 0.17 rev/s with an 79 kg man standing at a point 1.6 m from the axis of rotation.
dezoksy [38]

Hi there!

We can use the conservation of angular momentum to solve.

L_i = L_f\\\\I\omega_i = I\omega_f

I = moment of inertia (kgm²)

ω = angular velocity (rad/sec)

Recall the following equations for the moment of inertia.

\text{Solid cylinder:} I = \frac{1}{2}MR^2\\\\\text{Object around center:} = MR^2

Begin by converting rev/sec to rad sec:


\frac{0.17rev}{s} * \frac{2\pi rad}{1 rev} = 1.068 \frac{rad}{s}

According to the above and the given information, we can write an equation and solve for ωf.

1.068(\frac{1}{2}(34)(1.6)^2 + (79)(1.6)^2) = \omega_f(\frac{1}{2}(34)(1.6^2) + 79(0^2))\\\\\omega_f = \boxed{6.03 \frac{rad}{sec}}

4 0
2 years ago
A Level is set up midway between two wood hubs that are about 300 ft. apart. The rod reading on hub A is 9.09 ft. and the readin
Zarrin [17]

Answer:

<em>The correct difference is 3.44 ft</em>

Explanation:

The correct difference is given as

D=R_A-R_B

D=9.09-5.65

D=3.44 ft

4 0
3 years ago
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