Answer:
526.57 Pa
Explanation:
P ( pressure at the bottom of the container) = 1.049 × 10^5 pa
Using the formula of pressure in an open liquid
Pw ( pressure due to water) = ρhg where ρ is density of water in kg/m³, h is the height in meters, and g is acceleration due to gravity in m/s²
Pw = 1000 × 9.81 ×0.209 = 2050.29 Pa
P( atmospheric pressure) = 1.013 × 10^5 Pa
Pl ( pressure due to the liquid) = ρ(density of the liquid) × h (depth of the liquid) × g
Subtract each of the pressure from the absolute pressure at the bottom
P(bottom) - atmospheric pressure
(1.049 × 10^5) - (1.013 × 10^5) = 0.036 × 10^5 = 3600 Pa
subtract pressure due to water from the remainder
3600 - 2050.29 = 1549.71 Pa
1549.71 = ρ(density of the liquid) × h (depth of the liquid) × g
ρ (density of the liquid) = 1549.71 / (h × g) = 1549.71 / (0.3 × 9.81) =526.57 Pa
The distance a dropped object falls, with gravity and no air resistance:
Distance = (1/2) (acceleration) (falling time)²
Without air resistance, the horizontal motion has no effect on the fall.
Acceleration of Earth gravity = 9.8 m/s²
Distance = (1/2) (acceleration) (falling time)²
Distance = (1/2) (9.81 m/s²) (3.0 s)²
Distance = (0.5) x (9.81 m/s²) x (9.0 s²)
Distance = (0.5 x 9.81 x 9.0) (m-s² / s²)
Distance = 44.15 meters
We don't care how fast the bird was flying horizontally. It doesn't change anything. (It DOES determine how far ahead of the drop point the clam hits the ground. Most problems like this ask for that distance. This one didn't.)
It tells us the number of protons that are present in the nucleus, the positively charged region of that atom.
Imagine an incline of length "x". You let the toy go at the top of the incline and measure the time "t" it takes for it to get to the bottom.
The average speed would be "v=x/t".
