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taurus [48]
3 years ago
6

What information is needed to calculate the percent composition of a compound

Chemistry
2 answers:
IrinaVladis [17]3 years ago
6 0

Percent Composition by Mass. Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.

The best answer. :)

marysya [2.9K]3 years ago
5 0

Answer:

Molecular formula, molecular mass and the mass of each element in the molecule.

Explanation:

Percent Composition by Mass is the percentile of each element present in a molecule.

It is calculated by dividing the molar mass of a element  by the molecule molar mass, multiplied by 100

Eg the mass percent compositionof carbon in carbon dioxide is 27.27%

Molecular formula: CO2

Molecular Mass: 44g/mol

C molar mass: 12g/mol

O molar mass: 16g/mol

Percent_{carbon} =\frac{12}{44}*100=27.27

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a radioisotope has a half life of three hours how much of a 120g sample remains after 9 hours. what will the g amount be after 3
aksik [14]

\huge\boxed{♔︎Answer♔︎}

60g after 3 hours, 30g after 6 hours and 15g after 9 hours

Explanation:

Weight of the radioactive sample = 120g

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\textsf{ No. of half lives} =  \sf  \cancel\frac{3}{3}  = 1

The fraction of sample left

\sf  { \frac{1}{2} }^{1}  =  \frac{1}{2}

Mass of the sample left

\sf \frac{1}{2}  \times 120 =   \cancel\frac{120}{2}  = 60g

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(b) The weight of sample after 6 hours

\textsf{ No. of half lives} =  \sf   \cancel\frac{6}{3}  = 2

The fraction of the sample left

\sf   { \frac{1}{2} }^{2}  =  \frac{1}{2}  \times  \frac{1}{2}  =  \frac{1}{4}

Mass of the sample left

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The fraction of sample left

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Mass of sample left

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2 years ago
When a sample of aqueous hydrochloric acid was neutralized with aqueous sodium hydroxide in a calorimeter, the temperature of 10
Annette [7]
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Is Salt and pepper an example of a homogenous mixture?
alisha [4.7K]

Answer:

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4 years ago
Which statement is incorrect regarding the reaction of benzene with an electrophile? View Available Hint(s) A) The carbocation i
Leno4ka [110]

Answer:

The carbocation intermediate reacts with a nucleophile to form the addition product.

Explanation:

The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.

The general mechanism is shown in the figure.

i) Attack of the electrophile on the benzene (which is the nucleophile)

ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.

iii) the carbocation formation is the rate determining step.

iv) There is no formation of addition product.

Thus the wrong statement is

The carbocation intermediate reacts with a nucleophile to form the addition product.

3 0
4 years ago
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