All categories

3 years ago

What information is needed to calculate the percent composition of a compound

2 answers:

6 0

Percent Composition by Mass. Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.

The best answer. :)

marysya [2.9K]3 years ago

5 0

Answer:

Molecular formula, molecular mass and the mass of each element in the molecule.

Explanation:

Percent Composition by Mass is the percentile of each element present in a molecule.

It is calculated by dividing the molar mass of a element by the molecule molar mass, multiplied by 100

Eg the mass percent compositionof carbon in carbon dioxide is 27.27%

Molecular formula: CO2

Molecular Mass: 44g/mol

C molar mass: 12g/mol

O molar mass: 16g/mol

$Percent_{carbon} =\frac{12}{44}*100=27.27$

You might be interested in

An example of basic research is A) the development of new plastics that can be recycled. B) the study of the relationship betwee

elena-s [515]

Answer:

C) the study of the composition of the atom.

Explanation:

A research can be defined as a systematic investigation or careful consideration of study with respect to a particular problem using scientific methods such as collection of data, documenting critical information, analysis of data, and the establishment of facts in order to reach new conclusions.

Similarly, a basic research is an approach to research that's typically theoritical and it's aimed at developing a theory, searching for the truth or gain a better understanding about a phenomenon, subject, or basic laws on nature.

In this context, an example of basic research is the study of the composition of the atom.

An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such determines or defines the structure of a chemical element.

Generally, atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.

5 0

2 years ago

The combustion of ________ has added great quantities of carbon dioxide to the atmosphere. Group of answer choices

forsale [732]

Answer:

Fossil fuels.

Explanation:

A fossil fuel is a fuel obtained from nature such as crude oil, coal, wood etc. The burning of fossil fuels releases tremendous amounts of carbon IV oxide into the environment causing a myraid of environmental problems paramount among them is global warming with its attendant consequences.

7 0

3 years ago

Which statement best describes temperature? A.

USPshnik [31]

?? post the statements

4 0

3 years ago

Read 2 more answers

A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The

V125BC [204]

Taking into account the definition of calorimetry, the specific heat of metal is 0.165 $\frac{cal}{gC}$ .

<h3>Definition of calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

Q is the heat exchanged by a body of mass m.
C is the specific heat substance.
ΔT is the temperature variation.

<h3>Specific heat capacity of the metal</h3>

In this case, you know:

For metal:

Mass of metal = 50 g
Initial temperature of metal= 45 °C
Final temperature of metal= 11.08 ºC
Specific heat of metal= ?

For water:

Mass of water = 250 g
Initial temperature of water= 10 ºC
Final temperature of water= 11.08 ºC
Specific heat of water = 1.035 $\frac{cal}{gC}$

Replacing in the expression to calculate heat exchanges:

For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)

For water: Qwater= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:

- Qmetal = + Qwater

- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

Solving:

- Specific heat of metal× 50 g× (-33.92 C)= 1.035 $\frac{cal}{gC}$ × 250 g× 1.08 C

Specific heat of metal× 1696 g×C= 279.45 cal

Specific heat of metal= $\frac{279.45 cal}{1696 gC}$