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taurus [48]
3 years ago
6

What information is needed to calculate the percent composition of a compound

Chemistry
2 answers:
IrinaVladis [17]3 years ago
6 0

Percent Composition by Mass. Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.

The best answer. :)

marysya [2.9K]3 years ago
5 0

Answer:

Molecular formula, molecular mass and the mass of each element in the molecule.

Explanation:

Percent Composition by Mass is the percentile of each element present in a molecule.

It is calculated by dividing the molar mass of a element  by the molecule molar mass, multiplied by 100

Eg the mass percent compositionof carbon in carbon dioxide is 27.27%

Molecular formula: CO2

Molecular Mass: 44g/mol

C molar mass: 12g/mol

O molar mass: 16g/mol

Percent_{carbon} =\frac{12}{44}*100=27.27

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Answer:

The death of Jesus was a unique, one of a kind, once for all death that ransomed mankind from sin and satisfied the righteousness of God and made it possible for man to once again have a personal relationship with God. The simple definition of death is separation.

Explanation:

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3 years ago
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Name the bonds found between amino acids in a polypeptide chain
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Explanation:

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¿En qué ecosistema de Puerto Rico abunda más el pez Mero?
Sphinxa [80]

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Mostly abundant Coral reef ecosystem

Explanation:

We know that,

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3 0
4 years ago
Carbonic acid, H2CO3, has two acidic hydrogens. A solution containing an unknown concentration of carbonic acid is titrated with
stepan [7]

Answer:

1) Net ionic equation :

2H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)

2) 0.765 M is  the molarity of the carbonic acid solution.

Explanation:

1) In aqueous carbonic acid , carbonate ions and hydrogen ion is present.:

H_2CO_3(aq)\rightarrow 2H^+(aq)+CO_3^{2-}(aq) ..[1]

In aqueous potassium hydroxide , potassium ions and hydroxide ion is present.:

KOH(aq)\rightarrow K^+(aq)+OH^{-}(aq) ..[2]

In aqueous potassium carbonate , potassium ions and carbonate ion is present.:

K_2CO_3(aq)\rightarrow 2K^+(aq)+CO_3^{2-}(aq) ..[3]

H_2CO_3(aq)+2KOH(aq)\rightarrow K_2CO_3(aq)+2H_2O(l)

From one:[1] ,[2] and [3]:

2H^+(aq)+CO_3^{2-}(aq)+2K^+(aq)+2OH^{-}(aq)\rightarrow 2K^+(aq)+CO_3^{2-}(aq)+H_2O(l)

Cancelling common ions on both sides to get net ionic equation :

2H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)

2)

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2CO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\\M_1=?\\V_1=50.0 mL\\n_2=1\\M_2=3.840 M\\V_2=20.0 mL

Putting values in above equation, we get:

M_1=\frac{1\times 3.840 M\times 20.0 mL}{2\times 50.2 mL}=0.765 M

0.765 M is  the molarity of the carbonic acid solution.

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4 years ago
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