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1 year ago

Below is the thermochemical equation for the combustion of octane.

Chemistry

1 answer:

Gnom [1K]1 year ago

8 0

5mol produces -10.941KJ

4 mol let produces x KJ

Solve through proportion

5/-10.941=4/x
5x=-43.764
x=-43.764/5
x=8.756 KJ

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Problem Page A chemist measures the amount of bromine liquid produced during an experiment. He finds that of bromine liquid is p

masha68 [24]

The question is incomplete, here is the complete question:

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 766.g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced. Round your answer to 3 significant digits.

<u>Answer:</u> The amount of liquid bromine produced is 4.79 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of liquid bromine = 766. g

Molar mass of liquid bromine, $(Br_2)$ = 159.8 g/mol

Putting values in above equation, we get:

$\text{Moles of liquid bromine}=\frac{766.g}{159.8g/mol}=4.79mol$

Hence, the amount of liquid bromine produced is 4.79 moles.

6 0

3 years ago

What is the order of increasing rate of eusion for the following gases, Ar, CO2, H2, N2?

AVprozaik [17]

Answer:

H2 > N2 > Ar > CO2

Explanation:

Graham's law explains why some gases efuse faster than others. This is due to the difference i their molar mass. Generally; The rate of effusion of gaseous substances is inversely proportional to the square rot of its molar mass.

This means gases with low molar masses would have higher efusion rate compared to gases with higher molar masses.

So now we just need to compare the molar masses of the various gases;

Ar - 39.95

CO2 - 44.01

H2 - 2

N2 - 28.01

To obtain the order in increasing rate, we have to order the gases in decreasing molar mass. This order of increasing rate is given as;

H2 > N2 > Ar > CO2

8 0

3 years ago

What do the following organic chemicals have in common glyphosphate, lindane, 2,4-d, chlordane

otez555 [7]

Glyphosphate, lindane, 2,4-d, chlordane are organic compound that have chlorine in common.

<h3>What is Organic compound?</h3>

Organic compound are group of chemical substance that have carbon and hydrogen atoms in which the bonds are covalently linked together.

Therefore, Glyphosphate, lindane, 2,4-d, chlordane are organic compound that have chlorine in common and these chemicals are use as herbicides that is kill weeds, or to kill insects or pests because of chlorine present in it.

Learn more about organic compounds here.

brainly.com/question/14102593

5 0

2 years ago

The process by which waste products are eliminated from the cell by diffusion through the cell membrane is called _____.

madam [21]

Answer:

Exocytosis

Explanation:

8 0

2 years ago

Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I

Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, $1.077\times 10^9$

Explanation :

First we have to calculate the moles of iron.

$\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles$

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains $6.022\times 10^{23}$ number of iron atoms

So, 0.0519 mole of iron contains $0.0519\times 6.022\times 10^{23}=3.125\times 10^{22}$ number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = $\frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}$

Number of iron atoms are present in each red blood cell = $\frac{3.125\times 10^{22}}{2.90\times 10^{13}}$

Number of iron atoms are present in each red blood cell = $1.077\times 10^9$

Therefore, the number of iron atoms present in each red blood cell are, $1.077\times 10^9$

6 0

3 years ago