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statuscvo [17]
3 years ago
13

The sun and stars give off radiant energy.

Chemistry
2 answers:
Valentin [98]3 years ago
7 0

Answer:

C. Weather it is Moving Towards Us or Away From Us

Explanation:

Just took the test!

avanturin [10]3 years ago
5 0
<span>C.whether it is moving toward us or away from us
</span>
You might be interested in
The isotope 106 46Pd (106 on top and 46 on bottom)
vazorg [7]

Answer:

4. 60 neutrons.

Explanation:

The given isotopes;

         ¹⁰⁶₄₆Pd

In this isotope, we can deduce that the mass number is the superscript and the atomic number is the subscript;

     Mass number  = 106

     Atomic number  = 46

Mass number is the number of protons and neutrons in an atom;

       Mass number = Protons + neutrons

Atomic number is the number of protons

   

So,  Number of protons  = 46

Number of neutrons  = Mass number  - Atomic number

                                    = 106  - 46

                                     = 60

Number of neutrons  = 60

7 0
3 years ago
Calculate the equilibrium constant k for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 k. express your
k0ka [10]
We cannot solve this problem without using empirical data. These reactions have already been experimented by scientists. The standard Gibb's free energy, ΔG°, (occurring in standard temperature of 298 Kelvin) are already reported in various literature. These are the known ΔG° for the appropriate reactions.

<span>glucose-1-phosphate⟶glucose-6-phosphate          ΔG∘=−7.28 kJ/mol
fructose-6-phosphate⟶glucose-6-phosphate          ΔG∘=−1.67 kJ/mol
</span>
Therefore, the reaction is a two-step process wherein glucose-6-phosphate is the intermediate product.

glucose-1-phosphate⟶glucose-6-phosphate⟶fructose-6-phosphate 

In this case, you simply add the ΔG°. However, since we need the reverse of the second reaction to end up with the terminal product, fructose-6-phosphate, you'll have to take the opposite sign of ΔG°.

ΔG°,total = −7.28 kJ/mol  + 1.67 kJ/mol = -5.61 kJ/mol

Then, the equation to relate ΔG° to the equilibrium constant K is

ΔG° = -RTlnK, where R is the gas constant equal to 0.008317 kJ/mol-K.
-5.61 kJ./mol = -(0.008317 kJ/mol-K)(298 K)(lnK)
lnK = 2.2635
K = e^2.2635
K = 9.62


6 0
3 years ago
Read 2 more answers
Please help!! I was sick when he went over this
Alexus [3.1K]

Answer:

5.70×10^-11 m

Explanation:

7 0
3 years ago
How did Wegener explain why fossils of land animals were found on continents that are across oceans from one another?
slamgirl [31]
He explained that with continental drift
8 0
3 years ago
Read 2 more answers
8. Calculate the number of moles of eachsubstance.a. 5.45 x 1026 particles of methane, CH4
Klio2033 [76]

<em>ANSWER</em>

The number of moles of methane is 905.32 moles

STEP-BY-STEP EXPLANATION:

Given information

The number of particles of methane = 5.45 x 10^26 particles

Let x represents the number of moles of methane

To calculate the number of moles, we will be using the below formula

\text{Number of particles = number of moles x Avogadro's constant}

Recall that, the Avogadro's constant is given as

6.02\cdot10^{23}\begin{gathered} 5.45\cdot10^{26}\text{ = x }\cdot\text{ 6.02 }\cdot10^{23} \\ \text{Divide both sides by 6.02 }\cdot10^{23} \\ x\text{ = }\frac{5.45\cdot10^{26}}{6.02\cdot10^{23}} \\ x\text{ = }\frac{5.45}{6.02}\cdot10^{26\text{ - 23}} \\ x\text{ = 0.9053 }\cdot10^3 \\ x\text{ = 905.32 moles} \end{gathered}

Therefore, the number of moles of methane is 905.32 moles

6 0
2 years ago
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