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diamong [38]
2 years ago
14

What Le Chatelier’s factors cause an increase in the concentration of Hb(CO)4(aq) in the Hb(CO)4(aq) + 4O2(g)Hb(O2)4(aq) + 4CO(g

)
Chemistry
1 answer:
Lyrx [107]2 years ago
3 0

Answer:

Explanation:

Hb(CO)4(aq) + 4O2(g)  ⇄  Hb(O2)4(aq) + 4CO(g)

1 )  If we increase the concentration of CO(g) , the reaction above will proceed in reverse direction to decrease its concentration,  according to Le Chatelier principle. Hence more of Hb(CO)4(aq) will be formed.

2 )  If we decrease the concentration of O₂ , then also , reaction will proceed in reverse direction . Hence concentration of Hb(CO)4(aq) will be increased .

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A 78.0 g sample of an unknown compound contains 12.4 g of hydrogen. what is the percent by mass of hydrogen in the compound?
AleksandrR [38]
Formula to find the percent composition of an element in a compound is \frac {MolarMassOfElement}{MolarMassOfCompound}*100.

Now enter the variables into the formula.

\frac {12.4}{78.0}*100 = 15.897%
Round to 3 significant figures. 15.897% = 15.9%

The answer is 15.9% H
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olga2289 [7]

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sertanlavr [38]

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Answer:

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Explanation:

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2h3po4 + 3mg(oh)2 → mg3(po4)2 + 6h2o phosphoric acid, h3po4, is neutralized by magnesium hydroxide, mg(oh)2, according to the eq
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The balanced equation for the neutralisation reaction is as follows
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