Explanation:
The reaction equation will be as follows.
Calculate the amount of 
dissolved as follows.
It is given that 
= 0.032 M/atm and 
= 
atm.
Hence, ![[CO_{2}]](https://tex.z-dn.net/?f=%5BCO_%7B2%7D%5D)
will be calculated as follows.
= 
= 
= 
or, = 
It is given that 
As, ![K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5E%7B2%7D%7D%7B%5BCO_%7B2%7D%5D%7D)
![4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}](https://tex.z-dn.net/?f=4.46%20%5Ctimes%2010%5E%7B-7%7D%20%3D%20%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5E%7B2%7D%7D%7B0.608%20%5Ctimes%2010%5E%7B-5%7D%7D)
![[H^{+}]^{2}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%5E%7B2%7D)
= 
![[H^{+}]](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D)
= 
Since, we know that pH = ![-log [H^{+}]](https://tex.z-dn.net/?f=-log%20%5BH%5E%7B%2B%7D%5D)
So, pH = 
= 5.7
Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.
The mass of a sample of alcohol is found to be = m = 367 g
Hence, it is found out that by raising the temperature of the given product, the mass of alcohol would be 367 g.
Explanation:
The Energy of the sample given is q = 4780
We are required to find the mass of alcohol m = ?
Given that,
The specific heat given is represented by = c = 2.4 J/gC
The temperature given is ΔT = 5.43° C
The mass of sample of alcohol can be found as follows,
The formula is c = 
We can drive value of m bu shifting m on the left hand side,
m = 
mass of alcohol (m) = 
m = 367 g
Therefore, The mass of the given sample of alcohol is
m = 367g
It requires 4780 J of heat to raise the temperature by 5.43 C in the process which yields a mass of 367 g of alcohol.
<span> indefinite volume </span>
<span>If the mass is definite and the density is definite, </span>
<span>then your volume is definite.</span>
From the chemical formula, 1 formula unit of KAl (SO4)2.12H2O
encompasses 1 atom of Al = 4 * 2 atoms of O in KAl (SO4)2 + 12 atoms of O in
12H2O which is equal to 20 atoms of O.
So, if you have 1.3 × 10^21 Al atoms, you have 20 * 1.3 × 10^21 O atoms will
now be equal to 2.6 * 10^22 atoms of O.
<span>Well, during the day, the water, as well as the surfaces surrounding the water, are heated by various thermodynamic processes: conduction, convection, radiation, etc. This in turn warms the water molecules in the lakes, streams, rivers, and oceans, thereby transferring heat (their kinetic energy) to the water molecules, which in turn receive that energy from the surrounding surfaces, or directly via radiation/insolation from the sun. When the water molecules attain enough energy, some of them attain enough energy to escape the surface of the liquid and enter the gas phase. Hence, as water is heated, more and more water molecules attain enough kinetic energy to enter the gas phase.</span>
