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OLga [1]
1 year ago
5

What is the equation of proton transfer between NaC6H5CO2 and H2O

Chemistry
1 answer:
Anna35 [415]1 year ago
4 0

The equation of the proton transfer is:

  • NaC₆H₅CO₂ + H₂O ⇄ C₆H₅CO₂H + NaOH

<h3>What are acids?</h3>

Acids according to the Bronsted-Lowry definition, are substances that donates one or more hydrogen ions to another substance in a chemical reaction.

The substances that receive the proton are called bases.

Hydrogen ions are considered as protons. The hydrogen ions produced by acids results in a pH of less than 7 for acid solutions.

Considering the given substances, the equation of the proton transfer is given below:

NaC₆H₅CO₂ + H₂O ⇄ C₆H₅CO₂H + NaOH

The compound NaC₆H₅CO₂, sodium benzoate, is a base and accepts protons from H₂O which serves as the acid.

H₂O serve as the acid by transferring protons to NaC₆H₅CO₂ and then, NaOH is formed.

Learn more about protons at: brainly.com/question/24084759

#SPJ1

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True or false: the hydrogen atom is most stable when it has a full octet of electrons.
Mazyrski [523]
<em>This statement is false.</em> When you say full octet, it means that an element opts to have eight electrons in its valence shell to become stable. However, since a hydrogen atom only has 1 electron when neutral, it is impossible to reach a full octet. That is why Hydrogen is one of the exceptions to this octet rule.
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3 years ago
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In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quan
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Answer:

Manganese, Fifth transition element

[X] 3d⁶ 4s¹

Iron, Sixth transition element

[X] 3d⁶ 4s²

Explanation:

Complete Question

In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quantum mechanics works as it does in our universe, except that there are six d orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the sixth and seventh elements in the first transition series in Universe L. Note; you may use [X] to stand for the electron configuration of the noble gas at the end of the row before the first transition series.

Solution

In our universe, there are 5 d orbitals.

And according to Aufbau's principles that electrons fill the lower energy orbitals before they fill higher energy orbitals and Hund's Rule that states that electrons are fed singly to all the orbitals of a subshell before pairing occurs.

The fifth and sixth transition elements in our universe is then Manganese and Iron respectively.

Manganese - [Ar] 3d⁵ 4s²

Iron - [Ar] 3d⁶ 4s²

So, in the new universe L, where there are six d orbitals, for manganese, the fifth transition metal, because half filled orbitals are more stable than partially filled orbitals (that woukd have been rhe case if we leave 5 electrons on the 3d orbital), the 4s orbital is filled to half of its capacity and the one electron removed from the 4s is used to fill the six 3d orbital to half of its capacity too.

For the sixth transition element, the new extra electron just fills the lower energy 4s orbital, leaving the six 3d orbitals all half-filled.

Hence, they both have ground state configurations of

- Manganese, Fifth transition element

[X] 3d⁶ 4s¹

- Iron, Sixth transition element

[X] 3d⁶ 4s²

Hope this Helps!!!

7 0
3 years ago
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Simply subtract 14 and 9.2 to find the pOH and then take the inverse log to find the OH concentration.

POH = 4.8

OH concentration = 1.58 X 10^-5 M.
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