Answer:
The heat capacity of the bomb calorimeter is 7.58 J/°C.
Explanation:
![C_6H_6(I) + \frac{15}{2} O_2 (g) \rightarrow 6CO_2 (g) + 3H_2O (g) ,\Delta H^o = -3267.5 kJ](https://tex.z-dn.net/?f=C_6H_6%28I%29%20%2B%20%5Cfrac%7B15%7D%7B2%7D%20O_2%20%28g%29%20%5Crightarrow%206CO_2%20%28g%29%20%2B%203H_2O%20%28g%29%20%2C%5CDelta%20H%5Eo%20%3D%20-3267.5%20kJ)
First, we will calculate energy released on combustion:
= enthalpy change = -3267.5 kJ/mol
q = heat energy released
n = number of moles benzene= ![\frac{\text{Mass of benzene}}{\text{Molar mass of benzene}}=\frac{2.15 g g}{78 g /mol}=0.02756 mol](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BMass%20of%20benzene%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20benzene%7D%7D%3D%5Cfrac%7B2.15%20g%20g%7D%7B78%20g%20%2Fmol%7D%3D0.02756%20mol)
![\Delta H=-\frac{q}{n}](https://tex.z-dn.net/?f=%5CDelta%20H%3D-%5Cfrac%7Bq%7D%7Bn%7D)
![q=\Delta H\times n =-3267.5 kJ/mol\times 0.02756 mol=-90.0657 kJ](https://tex.z-dn.net/?f=q%3D%5CDelta%20H%5Ctimes%20n%20%3D-3267.5%20kJ%2Fmol%5Ctimes%200.02756%20mol%3D-90.0657%20kJ)
q = -90.0657 kJ = -90,065.7 J
Now we calculate the heat gained by the calorimeter let it be Q.
Q = -q= -(-90,065.7 J) = 90,065.7 J (conservation of energy)
![Q=c\times (T_{final}-T_{initial})](https://tex.z-dn.net/?f=Q%3Dc%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29)
where,
Q = heat gained by calorimeter
c = specific heat capacity of calorimeter =?
= final temperature = ![34.34^oC](https://tex.z-dn.net/?f=34.34%5EoC)
= initial temperature = ![22.46^oC](https://tex.z-dn.net/?f=22.46%5EoC)
Now put all the given values in the above formula, we get:
![90,065.7 J=c\times (34.34-22.46)^oC](https://tex.z-dn.net/?f=90%2C065.7%20J%3Dc%5Ctimes%20%2834.34-22.46%29%5EoC)
![c=\frac{90,065.7 J}{(34.34-22.46)^oC}=7.58 J/^oC](https://tex.z-dn.net/?f=c%3D%5Cfrac%7B90%2C065.7%20J%7D%7B%2834.34-22.46%29%5EoC%7D%3D7.58%20J%2F%5EoC)
The heat capacity of the bomb calorimeter is 7.58 J/°C.
Answer:
I am pretty sure that it is A. H2.
Explanation:
Sorry if it's wrong.
Explanation:
if the first one was just O, then:
i) no of moles = mass/ molar mass
2= m/ 16
m = 16*2
m = 32g
ii) the second answer would be the same.
Hello,
Here is your answer:
The proper answer to this question is option C "stigma".
Here is how:
The stigma is responsible for producing pollen in a plant.
Your answer is C.
If you need anymore help feel free to ask me!
Hope this helps!
Answer:
○ Coefficients in chemical equations
Explanation:
Hope this helps!!!
_liyah