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kogti [31]
3 years ago
8

Has anyone ever done the model of an atom lab?

Physics
2 answers:
Elena L [17]3 years ago
7 0

Answer:

no

Explanation:

dsp733 years ago
3 0

Answer:

no i have not lol

Explanation:

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In order to catch a fast-moving softball with your bare hand, you extend your hand forward just before the catch and then let th
hichkok12 [17]
This is a concept of momentum. In equation, momentum is the product of force and distance. When a ball is thrown, its force is constant all throughout unless disturbed by an external force. Therefore, force is the constant of proportionality that relates momentum with distance. When you block a ball from a given distance, you would feel the great force on your hand. In order to reduce the force, you have to follow the direction of the force in order to minimize the impact. By doing this, you gradually decrease the momentum of the ball. 
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3 years ago
The electric potential at the origin of an xy-coordinate system is 40 V. A -8.0-μC charge is brought from x = +∞ to that point.
vredina [299]

Answer:

-320 μJ.

Explanation:

Consider a point with an electrical charge of q. Assume that V is the electrical potential at the position of that charge. The electrical potential of that point charge will be equal to:

\text{Potential Energy} = q \cdot V.

Keep in mind that since both q and V might not be positive, the size of the electrical potential energy might not be positive, either.

For this point charge,

  • q = \rm -8.0\; \mu C; (that's -8.0 microjoules, which equals to \rm -8.0\times 10^{-6}\; J)
  • V = \rm 40\; V.

Hence its electrical potential energy:

\text{Potential Energy} = q\cdot V = \rm (-8.0\; \mu C) \times 40\; V = -320\; \mu J.

Why is this value negative? The electrical potential energy of a charge is equal to the work needed to bring that charge from infinitely far away all the way to its current position. Also, negative charges are attracted towards regions of high electrical potential. Bringing this \rm -8.0\; \mu C negative charge to the origin will not require any external work. Instead, this process will release 320 μJ of energy. As a result, the electrical potential energy is a negative value.

7 0
3 years ago
If a non-rotating object has no acceleration, then we can say for certain that it is:__________
EleoNora [17]

We may be positive that an object is in mechanical equilibrium if it is not rotating and experiences no acceleration.

<h3>What is mechanical equilibrium?</h3>

There are numerous other definitions for mechanical equilibrium that are all mathematically comparable in addition to the definition in terms of force. A system is in equilibrium in terms of momentum if the component motions are all constant. If velocity is constant, the system is in equilibrium in terms of velocity. When an item is in a state of rotational mechanical equilibrium, its angular momentum is preserved and its net torque is zero. More generally, equilibrium is reached in conservative systems at a configuration space location where the gradient of the potential energy concerning the generalized coordinates is zero.

To learn more about mechanical equilibrium, visit:

<u>brainly.com/question/14246949</u>

#SPJ4

6 0
2 years ago
Which best describes the forces identified by Newton’s third law of motion?
egoroff_w [7]
<span>equal and acting on different objects</span>
4 0
3 years ago
Read 2 more answers
Consider two massless springs connected in parallel. Springs 1 and 2 have spring constants k1 and k2 and are connected via a thi
77julia77 [94]

Answer:

k1 + k2

Explanation:

Spring 1 has spring constant k1

Spring 2 has spring constant k2

After being applied by the same force, it is clearly mentioned that spring are extended by the same amount i.e. extension of spring 1 is equal to extension of spring 2.

x1 = x2

Since the force exerted to each spring might be different, let's assume F1 for spring 1 and F2 for spring 2. Hence the equations of spring constant for both springs are

k1 = F1/x -> F1 =k1*x

k2 = F2/x -> F2 =k2*x

While F = F1 + F2

Substitute equation of F1 and F2 into the equation of sum of forces

F = F1 + F2

F = k1*x + k2*x

= x(k1 + k2)

Note that this is applicable because both spring have the same extension of x (I repeat, EXTENTION, not length of the spring)

Considering the general equation of spring forces (Hooke's Law) F = kx,

The effective spring constant for the system is k1 + k2

3 0
3 years ago
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