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3 years ago

What is an example of a partially movable joint?

1 answer:

3 0

<span>A partially movable joint is a joint in which its movement is limited to a certain amount. They are usually supported by a layer of cartilages and fibrous connective tissues. They are also called amphiarthrosis joints. Example of this are the joints formed by adjacent vertebrae containing intervertebral disc of a cartilage. When the joints are moved, it limits its movement because of this arrangement. Other examples of this are the ribs and the sternum. Notice that you cannot twist your upper body at 360 degrees without moving your lower body.</span>

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increase of green house gases is warming the oceans and melting sea ice at the poles. This causes changes in climate. Name three

Ahat [919]

core, surface atmosphere

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3 years ago

Which example represents the impact of religion on culture in the United States? A. children receiving counseling at school B. f

dmitriy555 [2]

Answer:

D. Banks and offices closing on sunday.

Explanation:

Church is usually on sunday and people need a day off to do it because service is about 3 hours long. When banks and offices close on this day it shows how religion has affected our lives and our culture.

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3 years ago

The speed of sound is 346 m/s. If a sound wave travels at a frequency of 55 Hz, what would its wavelength be?

Korvikt [17]

Answer:

6.29 meters.

Explanation:

, where v is the speed of wave and f is the frequency of wave.

We are given that ,

The speed of sound is 346 m/s.

i..e v=346 m/s

A sound wave travels at a frequency of 55 H.

i..e f=55

the wavelength would be 6.29 meters.

This is based on another brainly answer

Link: brainly.com/question/12538018

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2 years ago

A 25,000 kg traveling east collides with a 2,000 kg truck standing still on the tracks. After the collision the train and truck

Elis [28]

Answer:

24.084 m/s

Explanation:

From the law of conservation of linear momentum

Total momentum before collision equals to the total momentum after collision

Since momentum=mv where m is mass and v is velocity

$M_{truck}V_{truck}=V_{common}*(M_{truck} +M_{standing})$ where $M_{truck}$ is the mass of the truck, $V_{truck}$ is velocity of the truck, $V_{common}$ is the common velocity of moving and standing truck after collision and $M_{standing}$ is the mass of the standing truck

Making $V_{truck}$ the subject we obtain

$V_{truck}=\frac { V_{common}*(M_{truck} +M_{standing})}{M_{truck}}$

Substituting $M_{truck}$ as 25000 Kg, $V_{common}$ as 22.3 m/s, $M_{standing}$ as 2000 Kg we obtain

$V_{truck}=\frac { 22.3 m/s *(25000 Kg +2000 Kg)}{25000}= 24.084 m/s$

Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive

The truck was moving at 24.084 m/s

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3 years ago

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3 years ago