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marin [14]
4 years ago
13

What is an example of a partially movable joint?

Physics
1 answer:
shtirl [24]4 years ago
3 0
<span>A partially movable joint is a joint in which its movement is limited to a certain amount. They are usually supported by a layer of cartilages and fibrous connective tissues. They are also called amphiarthrosis joints. Example of this are the joints formed by adjacent vertebrae containing intervertebral disc of a cartilage. When the joints are moved, it limits its  movement because of this arrangement. Other examples of this are the ribs and the sternum. Notice that you cannot twist your upper body at 360 degrees without moving your lower body.</span>
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Listed below are the measured radiation absorption rates​ (in W/kg) corresponding to 11 cell phones. Use the given data to const
Fantom [35]

Answer:

The 5-number summary is

1. Median = 0.93 W/kg

2. Lower quartile = 0.69 W/kg

3. Upper quartile = 1.16 W/kg

4. Minimum value = 0.54 W/kg

5. Maximum value = 1.42 W/kg

Explanation:

We are given the measured radiation absorption rates​ (in W/kg) corresponding to 11 cell phones.

1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57

What is 5-number summary?

A 5-number summary refers to a box plot that basically shows 5 statistical characteristics of a data set.

These statistical characteristics are:    

1. Median

2. Lower quartile

3. Upper quartile  

4. Minimum value  

5. Maximum value  

1. Median:

Arrange the data in ascending order

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

(n+1)/2 gives the median value of the data set.

(11 + 1)/2 = 6th position

Therefore, 0.93 W/kg is the median of the data set.

2. Lower quartile:

Divide the data set into two equal halfs (include median in both if n = odd)

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The lower quartile is the median of the lower half of the data set.

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

The median is 6/2 = 3rd position

Therefore, the lower quartile of the data set is 0.69 W/kg

3. Upper quartile:

Divide the data set into two equal halfs (include median in both if n = odd)

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The upper quartile is the median of the lower half of the data set.

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The median is 6/2 = 3rd position

Therefore, the upper quartile of the data set is 1.16 W/kg

4. Minimum value:

The minimum value is the least value in the data set.

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

Therefore, the minimum value of the data set is 0.54 W/kg

5. Maximum value  

The maximum value is the least value in the data set.

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

Therefore, the maximum value of the data set is 1.42 W/kg

The box plot is illustrated in the attached diagram.

6 0
3 years ago
10. A car starts from rest at a stop light and reaches 20 m/s in 3.5
liq [111]
B i believe not really sure but that math i did seems about right
3 0
4 years ago
Read 2 more answers
The floor leader of the major party that holds fewer seats in a house of congress is called _____. 1.the speaker of the house 2.
Svetlanka [38]

2.the minority leader

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4 years ago
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A rifle that shoots bullets at 471 m/s is to be aimed at a target 46.4 m away. If the center of the target is level with the rif
Genrish500 [490]

Answer:

The equation that will express this result os

h = 0 = vy t - 1/2 g t^2    so the net height traveled by the bullet is zero

vy t = 1/2 g t^2

vy = 1/2 g t

vy = 1/2 * 9.8 * t       you could use -9.8 to indicate vy and g are in different directions

tx = sx/ vx  = 46.4 / 471 = .0985 sec    time to travel up and down to original height

th = .0985 / 2 = .0493 sec        time to reach maximum height

vy = g ty = 9.8 * .0493 sec = .483 m/s    initial vertical speed

Sy = vy t - 1/2 g t^2 = .483 * .0493 - 1.2 9.8 (.0493^^2)

Sy = .0238 - 4.9 ( .0493)^2 = .0238 - .0119 = .0119 m

Height to which bullet will rise - if the gun is aimed at this height then in .0985 seconds the bullet will fall to zero height

Check:    .483 / 9.8 =  .0493   time to reach zero vertical speed

total travel time = 2 * .0493 = .0986 sec

471 * .0986 = 46.4 m   total distance traveled by bullet

7 0
3 years ago
A 0.15 kg baseball falls to the ground with an acceleration of 9.8 m/s2. What is the weight of the baseball?
mafiozo [28]
The weight of the baseball is 
B. 1.49 N
3 0
3 years ago
Read 2 more answers
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