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notsponge [240]

3 years ago

7

Which is the transfer of thermal energy in matter with no overall transfer of matter? If you copy the answer from the last quest

ion your wrong and you will be reported.
conduction
radiation
insulation
convection

2 answers:

kogti [31]3 years ago

8 0

I believe radiation is the correct answer

zzz [600]3 years ago

6 0

the answer is radiation

You might be interested in

Is the process of science described in this lesson similar to your initial ideas about how science is carried out? Explain why o

VARVARA [1.3K]

The process of science followed my initial ideas e because it involved experiments.

<h3>What is the process of science?</h3>

The process of science or the scientific method refers to the process which scientists follow in their discovery and explanation of natural phenomena.

The scientific method is given below:

making an observation,
develop a hypothesis,
making a prediction,
conducting an experiment
analyzing the results
propound a law

The process of science follows my initial ideas about the process of science because I always thought science involved experiments.

In conclusion, the process of science involves making hypothesis and conducting research.

Learn more about process of science at: brainly.com/question/17216882

#SPJ1

3 0

2 years ago

A spherical bowling ball with mass m = 4.1 kg and radius R = 0.117 m is thrown down the lane with an initial speed of v = 8.9 m/

Furkat [3]

Answer:

1) 23.45 rad/s²

2) 2.7 m/s²

3) t= 1.6 s

4) x ≈ 11 m

5) vfinal = 4.45 m/s

6) KErot = 16.2 J

KEtran = 41 J

KErot < KEtran

Explanation:

Step 1: Data given

mass bowling ball = 4.1 kg

radius = 0.117 meter

initial speed = 8.9 m/s

1) What is the magnitude of the angular acceleration of the bowling ball as it slides down the lane?

α = a / r = 2.774 m/s² / 0.117m = 23.45 rad/s²

2)What is magnitude of the linear acceleration of the bowling ball as it slides down the lane?

a = µ*g = 0.28 * 9.8m/s² = 2.744 m/s² ≈ 2.7 m/s²

3) How long does it take the bowling ball to begin rolling without slipping?

This begins when ω = v / r

with

⇒ ω = α*t = 23.45 rad/s² * t

⇒ v = Vo - a*t = 8.9m/s - 2.744m/s²*t

This gives us:

23.45rad/s² * t = (8.9m/s - 2.744m/s²*t) / 0.11m

2.744*t = 8.9 - 2.744*t

t = 8.9 / 5.488 = 1.622 s ≈ 1.6 s

4) How far does the bowling ball slide before it begins to roll without slipping?

x = Vo*t - ½at² = (8.9*1.622 - ½*2.744*(1.622)²) m = 10.82 m ≈ 11 m

5) What is the magnitude of the final velocity?

v = Vo - at = 8.9m/s - 2.744m/s² * 1.622s = 4.45 m/s

6) After the bowling ball begins to roll without slipping, compare the rotational and translational kinetic energy of the bowling ball:

trans KE = ½ * 4.1kg * (4.45m/s)² =40.595 J ≈ 41 J

I = (2/5)mr² = (2/5) * 4.1kg * (0.117m)² = 0.0224 kg·m²

ω = v/r = 4.45m/s / 0.117m = 38.03 rad/s, so

rot KE = ½Iω² = ½ * 0.0224kg·m² * (38.03rad/s)² = 16.2 J

16.2 J < 41 J

KErot < KEtran

(For a rolling solid sphere, KErot ≈ 2/5 * KEtran)

6 0

3 years ago

What is the period that corresponds to a<br> frequency of 39.5 Hz?<br> Answer in units of s.

tatiyna

The answer for the following problem is mentioned below.

<u><em>Therefore the time period is 0.02 seconds.</em></u>

Explanation:

Frequency:

The number of waves that pass a fixed place in a given amount of time. (or)

The number of waves that pas by per second.

The SI unit of the frequency is Hertz(Hz).

Time period:

The time taken for one complete cycle of vibration to pass a given point.

The SI unit of time period is seconds. (s)

Given:

Frequency (f) = 39.5 Hz

To calculate:

Time period (T)

We know;

According to the problem;

From the problem;

<u>f = </u> $\frac{1}{T}$ <u></u>

Where;

f represents the frequency

T represents the time period

f = $\frac{1}{39.5}$

f = 0.02 seconds

<u><em>Therefore the time period is 0.02 seconds.</em></u>

5 0

4 years ago

Estimate the number of photons emitted per second from 1.0 cm2 of a person's skin if a typical emitted photon has a wavelength o

Diano4ka-milaya [45]

Answer:

2.63 x 10^18

Explanation:

A = 1 cm^2 = 1 x 10^-4 m^2

λ = 10,000 nm = 10,000 x 10^-9 m = 10^-5 m

T = 37 degree C = 37 + 273 = 310 k

Energy of each photon = h c / λ

where, h is the Plank's constant and c be the velocity of light

Energy of each photon = (6.63 x 10^-34 x 3 x 10^8) / 10^-5 = 1.989 x 10^-20 J

Energy radiated per unit time = σ A T^4

Where, σ is Stefan's constant

Energy radiated per unit time = 5.67 x 10^-8 x 10^-4 x 310^4 = 0.05236 J

Number of photons per second = Energy radiated per unit time / Energy of

each photon

Number of photons per second = 0.05236 / (1.989 x 10^-20) = 2.63 x 10^18

4 0

3 years ago

A stretched rubber band is an example of which type potential energy

Alenkinab [10]

Answer: elastic potential energy

Explanation:

6 0

3 years ago

Read 2 more answers