Ask question

Ask question

All categories

notsponge [240]

3 years ago

7

Which is the transfer of thermal energy in matter with no overall transfer of matter? If you copy the answer from the last quest

ion your wrong and you will be reported.
conduction
radiation
insulation
convection

2 answers:

kogti [31]3 years ago

8 0

I believe radiation is the correct answer

zzz [600]3 years ago

6 0

the answer is radiation

You might be interested in

You must record your daily workouts on a

larisa [96]

I do a yoga mat that could be different to your answer

5 0

3 years ago

Read 2 more answers

Please help me, I’m confused on where to start.

zimovet [89]

Answer:

D

Explanation:

6 0

2 years ago

Read 2 more answers

A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further it will penetrate before

Darina [25.2K]

${\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\$

$\:\:\:\:\bullet\:\:\:\sf{First \: penetrating \: length\:(s_{1}) = 3 \: cm}$

$\\$

${\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\$

$\:\:\:\:\bullet\:\:\:\sf{Left \: Penetration \: length \: before \: it \: comes \: to \: rest \:( s_{2} )}$

$\\$

${\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\$

$\:\:\:\:\bullet\:\:\:\sf{Let \: Initial \: velocity = v\:m/s} \\\\$

$\:\:\:\:\bullet\:\:\:\sf{Left \: velocity \: after \: s_{1} \: penetration = \dfrac{v}{2} \:m/s} \\\\$

$\:\:\:\:\bullet\:\:\:\sf{s_{1} = \dfrac{3}{100} = 0.03 \: m}$

$\\$

☯ As we know that,

$\\$

$\dashrightarrow\:\: \sf{ {v}^{2} = {u}^{2} + 2as }$

$\\$

$\dashrightarrow\:\: \sf{ \bigg(\dfrac{v}{2} \bigg)^{2} = {v}^{2} + 2a s_{1}}$

$\\$

$\dashrightarrow\:\: \sf{ \dfrac{ {v}^{2} }{4} = {v}^{2} + 2 \times a \times 0.03 }$

$\\$

$\dashrightarrow\:\: \sf{ \dfrac{ {v}^{2} }{4} - {v}^{2} = 0.06 \times a }$

$\\$

$\dashrightarrow\:\: \sf{\dfrac{ - 3{v}^{2} }{4} = 0.06 \times a }$

$\\$

$\dashrightarrow\:\: \sf{a = \dfrac{ - 3 {v}^{2} }{4 \times 0.06} }$

$\\$

$\dashrightarrow\:\: \sf{ a = \dfrac{ - 25 {v}^{2} }{2}\:m/s^{2} ......(1) }$

$\\$

$\:\:\:\:\bullet\:\:\:\sf{ Initial\:velocity=v\:m/s} \\\\$

$\:\:\:\:\bullet\:\:\:\sf{ Final \: velocity = 0 \: m/s }$

$\\$

$\dashrightarrow\:\: \sf{ {v}^{2} = {u}^{2} + 2as}$

$\\$

$\dashrightarrow\:\: \sf{{0}^{2} = {v}^{2} + 2 \times \dfrac{ - 25 {v}^{2} }{2} \times s }$

$\\$

$\dashrightarrow\:\: \sf{ - {v}^{2} = - 25 {v}^{2} \times s }$

$\\$

$\dashrightarrow\:\: \sf{ s = \dfrac{ - {v}^{2} }{ - 25 {v}^{2} }}$

$\\$

$\dashrightarrow\:\: \sf{ s = \dfrac{1}{25} }$

$\\$

$\dashrightarrow\:\: \sf{ s = 0.04 \: m }$

$\\$

☯ For left penetration (s₂)

$\\$

$\dashrightarrow\:\: \sf{s = s_{1} + s_{2} }$

$\\$

$\dashrightarrow\:\: \sf{ 0.04 = 0.03 + s_{2}}$

$\\$

$\dashrightarrow\:\: \sf{ s_{2} = 0.04 - 0.03 }$

$\\$

$\dashrightarrow\:\: \sf{s_{2} = 0.01 \: m = {\boxed{\sf{\purple{1 \: cm }}} }}$

$\\$

$\star\:\sf{Left \: penetration \: before \: it \: come \: to \: rest \: is \:{\bf{ 1 \: cm}}} \\$

4 0

2 years ago

Compute the velocity of an electron that has been accelerated through a difference of potential of 100 volts. express your answe

Elodia [21]

The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 * $10^{6}$ m/s

Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.

By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.

given

charge of electron = 1.6 × $10^{-19}$ C

mass of electron = 9.1 × $10^{-31}$ kg

Force in an electric field = q*E

potential energy is stored in the form of work done

potential energy = work done = Force * displacement

= q * (E * d)

= q * (V) = 1.6 × $10^{-19}$ * 100

stored potential energy = kinetic energy in electric field

kinetic energy = 1/2 * m * $v^{2}$

= 1/2 * 9.1 × $10^{-31}$ * $v^{2}$

equation both the equations

1/2 * 9.1 × $10^{-31}$ * $v^{2}$ = 1.6 × $10^{-17}$

$v^{2}$ = 0.352 * $10^{14}$ m/s

$v^{2}$ = 35.2 * $10^{12}$

= 5.93 * $10^{6}$ m/s

To learn more about kinetic energy in electric field here

brainly.com/question/8666051

#SPJ4

3 0

1 year ago

Which factors affect heat transfer between a warm and a cool substance?

damaskus [11]

Factors that affect heat transfer are:

1) Difference in temperature,
2) Mass of the object
3) Specific heat of the object

Hope this helps!

8 0

3 years ago