How many moles are in 1.93 x 10^24 atoms of gold
2 answers:
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In this kind of exercises, you should use the "ideal gas" rules: PV = nRT
P should be in Pascal:
445mmHg = 59328Pa
1225mmHg = 163319Pa
V should be in cubic meter:
16L = 0.016 m3
R =
= constant
= 
==> P1 * V1 = P2 * V2
V2 =
= 
V2 = 0.00581 m3 = 5.81 L
P should be in Pascal:
445mmHg = 59328Pa
1225mmHg = 163319Pa
V should be in cubic meter:
16L = 0.016 m3
R =
==> P1 * V1 = P2 * V2
V2 =
V2 = 0.00581 m3 = 5.81 L