Answer:
force-strength,power or energy as an attribute of motion, movement or action. Example: Frictional force.
Answer:
1) true
2) false
3) false
4) true
5) true
6) true
7) true
8) false
9) true
10) false
i think these are correct if im wrong on a few im sorry. Hope this helps at least a bit. And if i do get some wrong you know just to pick the opposite answer.
Answer:
x = 6.94 m
Explanation:
For this exercise we can find the speed at the bottom of the ramp using energy conservation
Starting point. Higher
Em₀ = K + U = ½ m v₀² + m g h
Final point. Lower
= K = ½ m v²
Em₀ = Em_{f}
½ m v₀² + m g h = ½ m v²
v² = v₀² + 2 g h
Let's calculate
v = √(1.23² + 2 9.8 1.69)
v = 5.89 m / s
In the horizontal part we can use the relationship between work and the variation of kinetic energy
W = ΔK
-fr x = 0- ½ m v²
Newton's second law
N- W = 0
The equation for the friction is
fr = μ N
fr = μ m g
We replace
μ m g x = ½ m v²
x = v² / 2μ g
Let's calculate
x = 5.89² / (2 0.255 9.8)
x = 6.94 m
Answer:
All adjustments in issue include changes in energy. Energy is either delivered or consumed. The energy is often in the form of heat, however it might be in the form of sound or light.
Explanation:
this is in my own words btw:)
The complete question is
What modifications did kepler make to copernicus’s model? check all that apply. planetary orbits are elliptical. planets closer to the sun move faster. planets spin in an epicycle while orbiting earth. venus has phases due to its orbiting of the sun. earth’s rotation causes the rising and setting of the sun.
Answer:
Planetary orbits are elliptical.
Planets closer to the Sun move faster.
Explanation:
The first option is based on the first law that states that the planets orbit the sun in ellipses, with the sun at one focus of the ellipse.
The second option is based on the third law that states that the square of the time of revolution about the sun is directly proportional to the cube of the mean radius of orbit of the planet.
