Explanation:
<em>The height of the pendulum is measured from the lowest point it reaches (point 3). </em>
At 1, the kinetic energy of the pendulum is zero (because it is not moving), and it has maximum potential energy.
At 2, the pendulum has both kinetic and potential energy, and how much of each it has depends on its height—smaller the height greater the kinetic energy and lower the potential energy.
At 3, the height is zero; therefore, the pendulum has no potential energy, and has maximum kinetic energy.
At 4, the pendulum again gains potential energy as it climbs back up, Again how much of each forms of energy it has depends on its height.
At 5, the maximum height is reached again; therefore, the pendulum has maximum potential energy and no kinetic energy.
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50m
Explanation:
Displacement is the length of path traveled which is measured from start to the finishing of the path.
Analysis of the journey;
Starts from:
0 30m from right
15m to left
50m to right
The displacement is 50m from the starting point.
Distance is total path traveled and for this problem it is 30+ 15 + 50 = 95m
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displacement brainly.com/question/5461768
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Answer:
b. 0.25cm
Explanation:
You can solve this question by using the formula for the position of the fringes:

m: order of the fringes
lambda: wavelength 500nm
D: distance to the screen 5 m
d: separation of the slits 1mm=1*10^{-3}m
With the formula you can calculate the separation of two adjacent slits:

hence, the aswer is 0.25cm
Answer:
Atomic radius decreases moving from left to right across a period.
Explanation:
When we move left to right across a period, the size of atoms generally decreases. It is because within the period the outer electrons are in same valence shell and the number of electrons and proton increases moving from left to right across the the period. It increases the effective nuclear charge resulting in the increased attraction of electron to the nucleus that causes the decreased radius of the atoms.
<em>im confused hold on imma send you a link to the answer</em>Explanation: