Answer:
2.87m
Explanation:
Using the law of gravitation to solve this question
F = GMm/r²
G is the gravitational constant
M and m are the masses
r is the distance between the masses
Substitute the given values
G = 6.67×10^-11 m³/kgs²
M =8.8 x 10^6 kg
m = 5.6 x 10^5 kg
F =440N
400 = 6.67×10^-11×8.8 x 10^6 ×5.6 x 10^5/r²
400r² = 328.698×10
400r² = 3286.98
r² = 3286.98/400
r² = 8.21745
r = √8.21745
r = 2.87m
Hence the distance of separation is 2.87m
Answer:
a) 32.58 m/s²
b) 161.84 m/s
Explanation:
Initial velocity = u = 0
Final velocity = v = 145 m/s
Time taken = t = 4.45 s
s = Displacement of dragster = 402 m
a = Acceleration
The final velocity is greater than the velocity used to find the average acceleration due to the gear changes. The first gear in a dragster has the most amount of toque which means the acceleration will be maximum. The final gears have less torque which means the acceleration is lower here. The final gears have less acceleration but can spin faster which makes the dragster able to reach higher speeds but slowly.
The bag moves to the left.
This is because of Newton's third law of motion that states:
For every action force on a body, there is an opposite and equal reaction force.
Thus pushing the bag from the right makes it move to the left.
The correct answer for this question is this one: C) 2.5s. T<span>he period and frequency of a water wave if 4.0 complete waves pass a fixed point in 10 seconds is that 2.5 s
</span>
Here are the following choices:
<span>A) 0.25s
B) 0.40s
C) 2.5s
D) 4.0s</span>
