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Dahasolnce [82]
3 years ago
12

Student A states that when she sits down on a chair, she is exerting a force on the chair and that is all that happens. Student

B states that when she sits on a chair, the chair is actually exerting a force back on her in reaction to her force exerted upon the chair. Which student is correct and why?
A.
Student A is correct because Newton’s 1st Law of Motion states that if the chair exerted a force on the student, her motion would change.

B.
Student A is correct because Newton’s 3rd Law of Motion states that for every action there is an equal and opposite action and the chair does not show any action.

C.
Student B is correct because Newton’s 1st Law of Motion states that if the chair were to be exerting a force on the student, her motion would change.

D.
Student B is correct because Newton’s 3rd Law of Motion states that for every action there is an equal and opposite action and the chair’s action counteracts the student’s so that neither move.
Physics
1 answer:
zvonat [6]3 years ago
7 0

Answer:

C

Explanation:

I got it right on the test !!

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Answer:

the gauge pressure at the upper face of the block is 116 Pa

Explanation:

Given the data in the question;

A cubical block of wood, 10.0 cm on a side.

height h = 1.50 cm = ( 1.50 × ( 1 / 100 ) ) m = 0.0150 m

density ρ = 790 kg/m³

Using expression for the gauged pressure;

p-p₀ = ρgh

where, p₀ is atmospheric pressure, ρ is the density of the substance, g is acceleration due to gravity and h is the depth of the fluid.

we know that, acceleration due to gravity g = 9.8 m/s²

so we substitute

p-p₀ = 790 kg/m³gh × 9.8 m/s² × 0.0150 m

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Therefore, the gauge pressure at the upper face of the block is 116 Pa

4 0
3 years ago
A rocket is fired at 100 m/s at an angle of 37, what was its speed at the top of its path?
Nadusha1986 [10]

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A 17926-lb truck enters an emergency exit ramp at a speed of 75.6 ft/s. It travels for 6.4 s before its speed is reduced to 30.3
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Answer:

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I don’t think we can answer this question with the information given. ANY ball thrown with ANY initial velocity v will be observed at a height h twice and with a time interval Δt.
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Explanation:

5 0
4 years ago
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