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3 years ago

Are the arcs below congruent?

Mathematics

2 answers:

Hoochie [10]3 years ago

6 0

Answer:

There is not enough information

Step-by-step explanation:

In Circle 1

Minor Arc : $\widehat{AB}=140^{\circ}$

Radius = AO=OB

In Circle 2

Minor Arc : $\widehat{GH}=140^{\circ}$

Radius =OG =OH

We need to show that the arcs are congruent .

Since the length of the radii are not given .

So, There is not enough information to prove that the arcs are congruent.

Hence Option D is true.

NikAS [45]3 years ago

5 0

Answer:

Step-by-step explanation:

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First Let we solve the Original system of equations:

equation (1): $x+3y=5$

equation (2): $7x-8y=6$

Multiplying equation (1) by 7, we get

$7x+21y=35 -->(3)$

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Subtracting,

$29y=29$ implies $y=1$

Then $x=5-3(1)=2$

Thus the solution of the original equation is $x=2, y=1.$

Now Let we form the new equation:

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Equation 1 is replaced with the sum of equation 1 and a multiple of equation 2:

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3 years ago

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Write an equation parallel to the function y=2x+3 and goes through the point (1, -4)

sergey [27]

Answer:

y=2x-6

Step-by-step explanation:

Parallel functions are functions with the same slopes but are in different positions on the coordinate plane (for this case it means that they have different y- intercepts)

So this means that the function will have a slope of 2

To find the equation we must plug in the value (1, -4) and find the new y-intercept(c)

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This means that the parallel function that goes through the point (1,-4) is

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3 years ago

A plane flying over the ocean is on course to land on an aircraft carrier. The diagonal distance between the plane and the aircr

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Answer:

the plane's current height above the ocean is 3.42 miles

Step-by-step explanation:

Given that the diagonal distance between the plane and the aircraft carrier is 10 miles.

What we need to find is the vertical distance between the plane and the aircraft carrier which is the plane's current height above the ocean. This can be gotten using sine rule.

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