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mr Goodwill [35]
2 years ago
8

I'm not sure what the answer is

Chemistry
1 answer:
Talja [164]2 years ago
4 0

Answer:

I think is A

Explanation: i'm not sure if im right.

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a technician mixes 80 ml of a 5% solution with 10 ml of water. what is the final percentage strength of the solution prepared?
Vinvika [58]

A technician mixes 80 ml of a 5% solution with 10 ml of water.  the final percentage strength of the solution prepared is 40 %.

given that :

8 ml of a 5 % solution mix with 10 ml . that means the 80 mL of 5 % solution is diluted with water of 10 mL

therefore, 80 × 5 = 10 × x %

x % = 40 %

Therefore, the final percentage strength of the solution is 40 %

Thus, A technician mixes 80 ml of a 5% solution with 10 ml of water.  the final percentage strength of the solution prepared is 40 %.

To learn more about percentage strength here

brainly.com/question/17130362

#SPJ4

5 0
1 year ago
Sugar can be converted to carbon dioxide and water by burning in air or by metabolic reactions inside living cells. How are thes
rjkz [21]

Answer:

These reactions are similar because the process is similar and the products are carbon dioxide they are different because the substances are different to outgo these reactions

Explanation:

5 0
3 years ago
C + 2H2 -> CH4
ankoles [38]

Answer:

<u>C) 4</u>

Explanation:

<u>The reaction</u> :

  • C (s) + 2H₂ (g) ⇒ CH₄ (g)

       12g      4g             16g

Hence, based on this we can say that : <u>2 moles of hydrogen gas are needed to produce 16g of methane.</u>

<u />

<u>For 32g of methane</u>

  • Number of moles of H₂ = 32/16 × 2
  • Number of moles of H₂ = <u>4</u>
4 0
2 years ago
Read 2 more answers
The second-order rate constants for the reaction of oxygen atoms witharomatic hydrocarbons have been measured (R. Atkinson and J
Pepsi [2]

Answer:

A = 1,13x10¹⁰

Ea = 16,7 kJ/mol

Explanation:

Using Arrhenius law:

ln k = -Ea/R × 1/T + ln(A)

You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).

Using the values you will obtain:

y = -2006,9 x +23,147

As R = 8,314472x10⁻³ kJ/molK:

-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹

<em>Ea = 16,7 kJ/mol</em>

Pre-exponential factor is:

ln A = 23,147

A = e^23,147

<em>A = 1,13x10¹⁰</em>

<em></em>

I hope it helps!

6 0
3 years ago
3NO2 + H2O = 2 HNO3 + NO
ArbitrLikvidat [17]

Explanation:

is anyone here in the year 2018

8 0
3 years ago
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