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Mariulka [41]
3 years ago
14

What does converse mean

Chemistry
1 answer:
Xelga [282]3 years ago
8 0

Answer:

engage in conversation.

Explanation:

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Balance the equation by ion electron method
irina1246 [14]

Answer:i believe you are to decompose the formula (i think)

8 0
3 years ago
Given that the density of gold and sand are 19. 3 g/cm^3 and 2. 95 g/cm^3, respectively, and that the density of the mixture is
SOVA2 [1]

The percent by mass of gold in the mixture will be 34.5%.

How to calculate the percentage?

The following information can be deduced based on the information given:

Density of gold = 19.3 g/cm³.

Density of sand = 2.94 g/cm³

Density of mixture = 4.17 g/cm³

It should be noted that when we find the volume fo gold on a 1cm³ sample, then we can be able to find that mass. The volume of gold will be calculated thus:

4.17 = [(19.3x + 2.95(1 - x)]

4.17 = 19.3x + 2.95 - 2.95x

4.17 = 16.35x + 2.95

x = 0.0746cm³

The mass of gold will be:

= 0.0746 × 19.3

= 1.44

The percent by mass of gold in the mixture will be:

= 1.44/4.17 × 100

= 34.5%

In conclusion, the percent by mass of gold in the mixture will be 34.5%.

What is Mass?

Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia, or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.

The kilogram is the primary mass unit in the SI (kg). Even though weight is frequently measured using a spring scale rather than a balancing scale and directly compared with known masses, mass is not the same as weight in physics. Due to the lower gravity on the Moon, an object would weigh less than it does on Earth while maintaining the same mass. Given that weight is a force.

To learn more about  mass equation visit here:

brainly.com/question/19600926?referrer=searchResults

#SPJ4

3 0
2 years ago
Please help, this assignment is to hard for me. :(
iren [92.7K]

Answer:

603000 J

Explanation:

The following data were obtained from the question:

Energy required (Q) =...?

Mass (M) = 10000 g

Specific heat capacity (C) = 2.01 J/g°C

Overheating temperature (T2) = 121°C

Working temperature (T1) = 91°C

Change in temperature (ΔT) =.?

Change in temperature (ΔT) =T2 – T1

Change in temperature (ΔT) = 121 – 91

Change in temperature (ΔT) = 30°C

Finally, we shall determine the energe required to overheat the car as follow:

Q = MCΔT

Q = 10000 × 2.01 × 30

Q = 603000 J

Therefore, 603000 J of energy is required to overheat the car.

7 0
3 years ago
A student is trying to solve the following problem by selecting the tile shown.
Vlad [161]
In my opinion, the correct answer among the choices presented above is option D. A student is trying to solve the following problem by selecting the tile shown. With this method, t<span>here is nothing wrong. The problem is ready to be solved.

</span>
5 0
3 years ago
If you pump 40.088g of octane (C8H18) into your gas tank, how mant molecules of octane are you pumping
Sonbull [250]

Answer:

2.11 × 10²³ molecules of octane

Explanation:

Given data:

Mass of octane = 40.088 g

Molecules of octane = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

Number of moles of octane:

Number of moles = mass/ molar mass

Number of moles = 40.088 g / 114.23 g/mol

Number of moles =  0.351 mol

Number of molecules:

one mole of octane = 6.022 × 10²³ molecules of octane

0.351 mole of octane = 0.351 ×  6.022 × 10²³ molecules of octane

2.11 × 10²³ molecules of octane

6 0
3 years ago
Read 2 more answers
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