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Alex Ar [27]
3 years ago
10

If temperature is held constant for an ideal gas, as P and V change for a given gas sample, the PV of products will_____. increa

se decrease be constant change
Chemistry
2 answers:
noname [10]3 years ago
6 0

Answer:

The PV of products will be constant.

Explanation:

Ideal gas equation-   PV = nRT

where P is pressure of gas, V is volume of gas, n is number of moles of gas, R is gas constant and T is temperature (in Kelvin) of gas.

Now, number of moles of a gas remain constant with change in state variables.

So, if T is constant then the term "nRT" remins constant.

As PV is equal to nRT therefore PV will be constant if temperature is held constant.

In another way we can say if P is increased then V will decrease or vice versa.

vodka [1.7K]3 years ago
3 0

Answer:

PV=nRT

Explanation:

V=<u>R</u><u>T</u><u>n</u>

P

rearrangement gives

  • PV=nRT
  • R=<u>P</u><u>V</u>

nT

where P=pressure

V=volume

n=number of moles

R=ideal gas(0.0820atmdm/3 mol/k)

T=temperature in kelvin

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in order to find the molar mass of an unknown compound, a research scientist prepared a solution of 0.930 g of an unknown in 125
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Answer:

Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

Explanation:

Let's apply the formula for freezing point depression:

ΔT = Kf . m

ΔT = 74.2°C - 73.4°C → 0.8°C

Difference between the freezing T° of pure solvent and freezing T° of solution

Kf = Cryoscopic constant → 5.5°C/m

So, if we replace in the formula

ΔT = Kf . m → ΔT / Kf = m

0.8°C / 5.5 m/°C = m → 0.0516 mol/kg

These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg

0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:

Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

3 0
3 years ago
Jonathan used the following soil triangle to identify a sample of soil as sandy clay. Which description of soil likely allowed J
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Answer:

Mostly large grains, with a sticky texture, 55% sand, 40% clay, and 5% silt

Explanation: I took the test, hope it helps.

7 0
2 years ago
Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0
3 years ago
Read 2 more answers
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