Given the particle diagram:. At 101.3 kPa and 298 K, which element could this diagram represent?. 1. Rn 3. Ag. 2. Xe 4. Kr
2 answers:
The particle diagram is shown in figure
As the atoms in the given diagram are closely placed to each other it means that the inter molecular forces are strong and the thermal energy of molecules is low .
When intermolecular interactions are strong and thermal energy is low the atoms or particles have a definite shape and volume
in case of gas the intermolecular forces are very low and the thermal energy of atoms is very high so they are in random motion and do not have a definite shape or volume
Now in the given examples
Rn , Xe and Kr all are noble elements and are infact noble gas
So the diagram could not be for these three
The only elements Ag (silver) is solid out of the given four elements so the particle diagram is of Ag only
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Answer:
1. hydrogen - H
2. helium - He
3. sodium - Na
4. magnesium - Mg
5. potassium - K
Explanation:
Hydrogen is the element of group 1 and first period. The atomic number of hydrogen is 1 and the symbol of the element is H.
The electronic configuration of the element hydrogen is:-
Helium is the element of group 18 and first period. The atomic number of helium is 2 and the symbol of the element is He.
The electronic configuration of the element helium is:-
Sodium is the element of group 1 and third period. The atomic number of sodium is 11 and the symbol of the element is Na.
The electronic configuration of the element sodium is:-
Magnesium is the element of group 2 and third period. The atomic number of magnesium is 12 and the symbol of the element is Mg.
The electronic configuration of the element magnesium is:-
Potassium is the element of group 1 and forth period. The atomic number of potassium is 19 and the symbol of the element is K.
The electronic configuration of the element potassium is:-
The question is incomplete, complete question is :
Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? ( for HF is
.)
[HF] = 0.280 M
Express your answer to two decimal places.
Answer:
The pH of an 0.280 M HF solution is 1.87.
Explanation:3
Initial concentration if HF = c = 0.280 M
Dissociation constant of the HF =
Initially
c 0 0
At equilibrium :
(c-x) x x
The expression of disassociation constant is given as:
Solving for x, we get:
x = 0.01346 M
So, the concentration of hydrogen ion at equilibrium is :
The pH of the solution is ;
The pH of an 0.280 M HF solution is 1.87.