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Aleksandr-060686 [28]
2 years ago
15

Given the particle diagram:. At 101.3 kPa and 298 K, which element could this diagram represent?. 1. Rn 3. Ag. 2. Xe 4. Kr

Chemistry
2 answers:
Sindrei [870]2 years ago
5 0

The particle diagram is shown in figure

As the atoms in the given diagram are closely placed to each other it means that the inter molecular forces are strong and the thermal energy of molecules is low .

When intermolecular interactions are strong and thermal energy is low the atoms or particles have a definite shape and volume

in case of gas the intermolecular forces are very low and the thermal energy of atoms is very high so they are in random motion and do not have a definite shape or volume

Now in the given examples

Rn , Xe and Kr all are noble elements and are infact noble gas

So the diagram could not be for these three

The only elements Ag (silver) is solid out of the given four elements so the particle diagram is of Ag only

slavikrds [6]2 years ago
3 0
3. Ag is the answer  .......
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Answer:

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Explanation:

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Liquid nitrogen has a density of 0.808 g/mL and boils at 77 K. Researchers often purchase liquid nitrogen in insulated 195-L tan
Reika [66]

Answer:

The nswer to the question is

The maximum fraction of the air in the room that could be displaced by the gaseous nitrogen is 0.548 or 54.8 %

Explanation:

To solve the question we note that

The density of the liquid nitrogen = 0.808g/mL and the volume is 195 L tank (vaporised)

Therefore since density = mass/volume we have

mass = Density × volume = 0.808 g/mL × 195 L × 1000 ml/L =157560 g

In gaseous form the liquid nitrogen density =1.15 g/L

That is density = mass/volume and volume = mass/density = 157560 g/(1.15g/L)  or

volume = 137008.69565 L

The dimension of the room = 10 m × 10 m × 2.5 m = 250 m³ and

1 m³ is equivalent to 1000 L, therefore 250 m³ = 250 m³  × 1000 L/m³ = 250000L

Therefore fraction of the volume occupied by the gaseous nitrogen =

137008.69565 L/250000 L = 0.548

Therefore the gaseous nitrogen occpies 54.8% of the room

7 0
2 years ago
How does the size change when an atom forms a cation and when an atom forms an anion?
mario62 [17]
<span>A cation is an atom that loses a valence electron. When a valence electron is released there is one electron less to create a repulsive force. The loss of a repulsive force will allow the atom to pull tighter together. An anion would therefore be larger in size due to increased repulsion of the valence electrons.</span>
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A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature
Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

  • v_0=500
  • \alpha =1.12\times 10^{-4}
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Now,

Increase in volume will be:

⇒ \Delta V = \alpha\times v_0\times \Delta \epsilon

By putting the given values, we get

           =1.12\times 10^{-4}\times 500\times 25

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           =1.4  \ mL

8 0
3 years ago
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