Question

Exit ticket: A lamp is plugged into a 110 Volt electrical outlet. There is a 9 Watt LED bulb in the lamp. a. What is

Answer 1

Answer:

(a) 0.081 A (b) 1358.02 ohms

Explanation:

Voltage, V = 110 volt

Power of a LED bulb, P = 9 Watt

(a) Let the current is I. The formula for ower in terms of voltage and power is given by :

P = VI

$I=\dfrac{P}{V}\\\\I=\dfrac{9}{110}\\\\=0.081\ A$

(b) Let R is the resistance of the bulb. Using Ohm's law as follows :

V = IR

$R=\dfrac{V}{I}\\\\R=\dfrac{110}{0.081}\\\\=1358.02\ \Omega$

Hence, this is the required solution.