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rodikova [14]
3 years ago
13

Exit ticket: A lamp is plugged into a 110 Volt electrical outlet. There is a 9 Watt LED bulb in the lamp. a. What is

Physics
1 answer:
notka56 [123]3 years ago
5 0

Answer:

(a) 0.081 A (b) 1358.02 ohms

Explanation:

Voltage, V = 110 volt

Power of a LED bulb, P = 9 Watt

(a) Let the current is I. The formula for ower in terms of voltage and power is given by :

P = VI

I=\dfrac{P}{V}\\\\I=\dfrac{9}{110}\\\\=0.081\ A

(b) Let R is the resistance of the bulb. Using Ohm's law as follows :

V = IR

R=\dfrac{V}{I}\\\\R=\dfrac{110}{0.081}\\\\=1358.02\ \Omega

Hence, this is the required solution.

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Kilowatt per hour

Explanation:

The energy is equal to the power by time.

E=\frac{P}{t}

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Action potentials _______.(A) are only found at the axon hillock and along the axon.(B) Two of the answers are correct.(C) are v
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A ball is moving with velocity 5 m/s in a direction which makes an angle of 30° with horizontal (i.e. with positive x-direction)
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Explanation:

(a)

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v_{1 \ x } = 5 \ cos \ 30^0

v_{1x} = 4.33 \ m/s

The component along the y-axis = v_2 { \ sin \  \theta}

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To find the final velocity( reflected velocity)

using the same magnitude v_2 = 5 \ m/s

The angle from the x-axis can be \theta_r = 90^0+60^0

= 150°

Thus, the component along the x-axis = v_2  \ cos \theta _r

v_{2x} = - 0.433 \ m/s

The component along the y-axis = v_2 \ sin \theta_r

v_{2y} = 5 \ sin \ 150^0

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(b)

The velocity v_1 can be written as in vector form.

v_1 ^{\to}  = v_1 x \hat {i} + v_1 y \hat {j}

v_1 ^{\to}  =4.33 \ \hat {i} +  2.5 \  \hat {j}  ----  (1)

The reflected velocity in vector form can be computed as:

v_2 ^{\to}  = v_2 x \hat {i} + v_2 y \hat {j}

v_2 ^{\to}  =-4.33 \ \hat {i} +  2.5 \  \hat {j}  --- (2)

The change in velocity = v_2 ^{\to} - v_1 ^{\to}

\Delta v ^{\to} = - 4.33 \hat i + 2.5 \hat j - 4.33 \hat i - 2.5 \hat j

\Delta v ^{\to} = - 8.66 \hat  { i }

(c)

The magnitude of change in velocity = | \Delta V |

| \Delta V | = 8.66 m/s

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