Question

The wheelchair starts from rest. It accelerates at a constant rate until it has a speed of 1.5 m/s. The wheelchair travels a distance of 2.0 m while it is accelerating. Calculate the acceleration of the wheelchair.
Please help me i have a test and i have zero idea how to do thiss............

Answer 1

Answer:-

$\pink{\bigstar}$ The acceleration of the wheelchair is $\large\leadsto\boxed{\tt\purple{0.5625 \: m/s^2}}$

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• Given:-

• Initial velocity of the wheelchair = 0 m/s

• Final velocity of the wheelchair = 1.5 m/s

• Distance covered by the wheelchair = 2 m

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• To Find:-

• Acceleration of the wheelchair = ?

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• Solution:-

We know,

• Third Equation of Motion:-

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{v^2 - u^2 = 2as}}}$

where,

• u = Initial velocity

• v = Final velocity

• a = Acceleration

• s = Distance covered

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• Substituting the values in the Formula:-

➪ $\sf (1.5)^2 - (0)^2 = 2 \times a \times 2$

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➪ $\sf 2.25 - 0 = 4 \times a$

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➪ $\sf 2.25 = 4 \times a$

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➪ $\sf a = \dfrac{2.25}{4}$

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★ $\large{\bold\red{a = 0.5625 \: m/s^2}}$

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Therefore, the acceleration of the wheelchair is 0.5625 m/s².