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nekit [7.7K]
3 years ago
11

The distance between the ruled lines on a diffraction grating is 1900 nm. The grating is illuminated at normal incidence with a

parallel beam of white light in the 400 nm to 700 nm wavelength band. What is the angular width of the gap between the first order spectrum and the second order spectrum
Physics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

3.28 degree

Explanation:

We are given that

Distance between the ruled lines on a diffraction grating, d=1900nm=1900\times 10^{-9}m

Where 1nm=10^{-9} m

\lambda_2=400nm=400\times10^{-9}m

\lambda_1=700nm=700\times 10^{-9}m

We have to find  the angular width of the gap between the first order spectrum and the second order spectrum.

We know that

\theta=sin^{-1}(\frac{m\lambda}{d})

Using the formula

m=1

\theta_1=sin^{-1}(\frac{1\times700\times 10^{-9}}{1900\times 10^{-9}})

\theta=21.62^{\circ}

Now, m=2

\theta_2=sin^{-1}(\frac{2\times400\times 10^{-9}}{1900\times 10^{-9}})

\theta_2=24.90^{\circ}

\Delta \theta=\theta_2-\theta_1

\Delta \theta=24.90-21.62

\Delta \theta=3.28^{\circ}

Hence, the angular width of the gap between the first order spectrum and the second order spectrum=3.28 degree

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