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3 years ago

12

A child attaches a rubber ball to a string and whirls it around in a circle overhead. If the string is 0.2m long and the ball's

speed is 16 m/s, what is the ball's centripetal acceleration?

1 answer:

AlladinOne [14]3 years ago

4 0

Answer:

The centripetal acceleration, $a_c = 1280 m/s^2$

Explanation:

Centripetal acceleration is given by the formula:

$a_c = \frac{v^2}{r}$

Where the speed of the ball, v = 16 m/s

Length of the string, r = 0.2 m

Substituting these parameters into the centripetal equation above:

$a_c = \frac{16^2}{0.2}\\a_c = \frac{256}{0.2}\\a_c = 1280 m/s^2$

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Calculate the current through a 3.0 Ď‰ resistor with a voltage of 9.0 v across it.

gulaghasi [49]

Answer: 3 A

Explanation:

According to<u> Ohm's law</u>:

$V=R.I$

Where:

$V=9 V$ is the voltage

$R=3\Omega$ is the resistance of the resistor

$I$ is the electric current (the value we want to find)

Isolating $I$ :

$I=\frac{V}{R}$

$I=\frac{9 V}{3\Omega}$

Finally:

$I=3 A$

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3 years ago

f your risk-aversion coefficient is A = 4 and you believe that the entire 1926–2015 period is representative of future expected

siniylev [52]

Answer:

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

Explanation:

As the complete question is not given here ,the table of data is missing which is as attached herewith.

From the maximized equation of the utility function it is evident that

$Weight=\frac{E_M-r_f}{A\sigma_M^2}$

For the equity, here as

$Weight$ is percentage of the equity which is to be calculated
${E_M-r_f}$ is the Risk premium whose value as seen from the attached data for the period 1926-2015 is 8.30%
$A$ is the risk aversion factor which is given as 4.
$\sigma_M$ is the standard deviation of the portfolio which from the data for the period 1926-2015 is 20.59

By substituting values.

$Weight=\frac{E_M-r_f}{A\sigma_M^2}\\Weight=\frac{8.30\%}{4(20.59\%)^2}\\Weight=0.4894 =48.94\%$

So the weight of equity is 48.94%.

Now the weight of T bills is given as

$Weight_{T-Bills}=1-Weight_{equity}\\Weight_{T-Bills}=1-0.4894\\Weight_{T-Bills}=0.5105=51.05\%\\$

So the weight of T-bills is 51.05%.

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

7 0

3 years ago

Having aced your Physics 2111 class, you get a sweet summer-job working in the International Space Station. Your room-mate, Cosm

Sphinxa [80]

Answer:

a

The speed is $s = 5.857 m/s$

b

The distance is $D = 22.4 \ m$

Explanation:

From the question we are told that

The speed of the banana is $v = 16 \ m/s$

The distance from my location is $d = 8.2 \ m$

The time taken is $t = 1.4 \ s$

The speed of the ice cream is

$s = \frac{d}{t}$

substituting values

$s = \frac{8.4}{1.4}$

$s = 5.857 m/s$

The distance of separation between i and Valdimir is the same as the distance covered by the banana

So

$D = v * t$

substituting values

$D = 16 * 1.4$

$D = 22.4 \ m$

3 0

3 years ago

Is it possible for an object that has a constant negative acceleration to change the direction in which it is moving? Explain wh

lozanna [386]

Yes! I think there are two ways you could go with this answer: 1) Acceleration is the change in velocity over time, it can be negative or positive. If you have an object that is already moving forwards in a straight line and give it a constant negative acceleration, it will slow down and then start going in reverse. 2)Velocity is a vector, meaning it has both magnitude and direction. In the example above, the acceleration is due to a change in magnitude, or speed (from +ve to -ve) but not a change in direction. Something that has constant speed but is changing direction is also accelerating (like something that is orbiting). You could use the earth as an example, which is constantly accelerating due to moving in a circle around the sun. At any time in the year you can say that in half a year's time the earth's direction will be reversed.

4 0

3 years ago

Two cars are initially separated by 2500 m and traveling towards each other. One car travels at 4.5 m/s and the second car trave

mylen [45]

Answer:

714.285s

Explanation:

use relative velocity

8-4.5 = 3.5m/s

x = 2500m

2500/3.5 = 714.285s = 700s (with sig figs)

7 0

3 years ago