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Alex Ar [27]
3 years ago
10

A 1000 kg car experiences a net force of 9500 N while slowing down from 30 m/s to 16 m/s. How far does it travel while slowing d

own?
Physics
1 answer:
rjkz [21]3 years ago
5 0

Answer:

33.89 m

Explanation:

We must first obtain the acceleration of the car from;

F=ma

Where

F= force= 9500 N

m= mass of the car= 1000kg

a= acceleration

a= F/m= 9500/1000

a= 9.5 m/s^2

From;

V^2=u^2 + 2as

Where;

V= final velocity

u= initial velocity

s= distance covered

a= acceleration

s= v^2 -u^2/2a

s= (30)^2 -(16)^2/2×9.5

s= 900 - 256/19

s= 644/19

s= 33.89 m

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masha68 [24]
Acceleration (magnitude anyway) = (change in speed) / (time for the change) .

Change in speed = (10 - 30) = -20 m/s

Time for the change = 4.0sec

Magnitude of acceleration = -20/4  =  <em>-5 m/s² </em>
3 0
3 years ago
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How much work is done by a 120N force applied to a box that moves 5m?
Vsevolod [243]

Answer:

600 Joules

Explanation:

Using the formula F*d*cosФ. Assuming the Ф is parallel to the motion. The work done is 600 Joules.

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State characteristics of the images formed by pin - hole camera​
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Real image

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Pls help ASAP now! This is physical science
const2013 [10]

Option A is correct answer

6 0
3 years ago
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A boy on board a cruise ship drops a 30. 0 gm marble into the ocean. If the resistive force proportionality constant is 0. 500 k
svlad2 [7]

The terminal speed of the marble is 0.588 m/s.

<h3>Calculation:</h3>

We know that,

F = mg                                                   ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k                                                       ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k                                                         .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k              

v = 0.03(9.8)/ 0.500

  = 0.294/0.500

  = 0.588 m/s

​

Hence, the terminal speed of the marble is 0.588 m/s.

Learn more about calculation of force here:

brainly.com/question/15562875

#SPJ4

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