Question

A 1000 kg car experiences a net force of 9500 N while slowing down from 30 m/s to 16 m/s. How far does it travel while slowing down?

Answer 1

Answer:

33.89 m

Explanation:

We must first obtain the acceleration of the car from;

F=ma

Where

F= force= 9500 N

m= mass of the car= 1000kg

a= acceleration

a= F/m= 9500/1000

a= 9.5 m/s^2

From;

V^2=u^2 + 2as

Where;

V= final velocity

u= initial velocity

s= distance covered

a= acceleration

s= v^2 -u^2/2a

s= (30)^2 -(16)^2/2×9.5

s= 900 - 256/19

s= 644/19

s= 33.89 m