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andrew-mc [135]
2 years ago
15

Plzzzzzzzzzzzzzzzzzzzzzzzzz help me i swear will mark you brainiest

Chemistry
1 answer:
Whitepunk [10]2 years ago
8 0

Answer:

The combustion of hydrogen–oxygen mixtures is used to produce very high temperatures (approximately 2500 °C) needed for certain types of welding operations. Consider the reaction to be

H2(g)+1/2O2(g)=H2O(g)

change in enthalpy is -241.8 kJ

What is the quantity of heat evolved, in kilojoules, when a 160  g mixture containing equal parts of  H2 and O2 by mass is burned?

Explanation:

i hope this help sorry if it does not ok bye luv!!!

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drek231 [11]

I believe that the best answer among the choices provided by the question is B. the density of freshwater remains constant as temperature decreases

6 0
3 years ago
Read 2 more answers
The electronic configuration of an element is given below.
drek231 [11]

Answer:

C. It is reactive because it must gain two electrons to have a full outermost energy level.  

Step-by-step explanation:

The electron configuration of this element ends in 2s²2p⁴.

A filled energy level would end in 2s²2p⁶.

The element will be reactive, because it must gain electrons to have a full energy level, and it needs two more electrons to do this.

4 0
3 years ago
Calculate the ph of sweater which has a hydrogen ion concentration of 1 times 10 to the power of 8
telo118 [61]

Answer:

The pH of the sweater containing Hydrogen ion concentration

[H^{+}]=1\times 10^{-8} is

<u>8</u>

<u></u>

Explanation:

pH = It is the negative logarithm of activity (concentration) of hydrogen ions.

pH = -log([H+])

Now, In the question the concentration of [H+] ions is :

[H^{+}]=1\times 10^{-8}

pH = -log(1\times 10^{-8})

use the relation:

log(10^{-a})=a

pH= -(-8)

pH = 8

Note : <em><u> 1 times 10 to the power of 8 must be" 1 times 10 to the power of -8"</u></em>

If the concentration is

[H^{+}]=1\times 10^{8}

Then pH = -8 , which is not possible . So in that  case the pH calculation is by other method

5 0
3 years ago
Calculate the freezing point (0°C) of a 0.05500 m aqueous solution of glucose.
Rainbow [258]

Answer:

-0.1767°C (Option A)

Explanation:

Let's apply the colligative property of freezing point depression.

ΔT = Kf . m. i

i = Van't Hoff factot (number of ions dissolved). Glucose is non electrolytic so i = 1

m = molality (mol of solute / 1kg of solvent)

We have this data → 0.095 m

Kf is the freezing-point-depression constantm 1.86 °C/m, for water

ΔT = T° frezzing pure solvent - T° freezing solution

(0° - T° freezing solution) = 1.86 °C/m . 0.095 m . 1

T° freezing solution = - 1.86 °C/m . 0.095 m . 1 → -0.1767°C

4 0
2 years ago
1. Atoms are
natita [175]

Answer:

a.the smallest building blocks of matter

Explanation:

because atoms are the smallest building blocks of matter.

3 0
3 years ago
Read 2 more answers
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