Plzzzzzzzzzzzzzzzzzzzzzzzzz help me i swear will mark you brainiest

Chemistry

1 answer:

Whitepunk [10]3 years ago

8 0

Answer:

The combustion of hydrogen–oxygen mixtures is used to produce very high temperatures (approximately 2500 °C) needed for certain types of welding operations. Consider the reaction to be

H2(g)+1/2O2(g)=H2O(g)

change in enthalpy is -241.8 kJ

What is the quantity of heat evolved, in kilojoules, when a 160 g mixture containing equal parts of H2 and O2 by mass is burned?

Explanation:

i hope this help sorry if it does not ok bye luv!!!

You might be interested in

What is the molarity of 1 mole of HCl in 5 liters of solution?

kicyunya [14]

Molarity = moles of solute(HCl)
------------------------------------
volume of the solution

= 1
------
5

= 0.2M.

Hence option B is correct.
Hope this helps!!

5 0

3 years ago

Read 2 more answers

Urgent! <br> which element do you think has a greater mass? cadmium or zinc?

Alex Ar [27]

Answer:

zinc

Explanation:

5 0

3 years ago

Read 2 more answers

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

scoray [572]

Answer:

70.77 g/mol is the molar mass of the unknown gas.

Explanation:

Effusion is defined as rate of change of volume with respect to time.

Rate of Effusion= $\frac{Volume}{Time}$

Effusion rate of oxygen gas after time t = $E=\frac{4.64 mL}{t}$

Molar mass of oxygen gas = M = 32 g/mol

Effusion rate of unknown gas after time t = $E'=\frac{3.12 mL}{t}$

Molar mass of unknown gas = M'

The rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$