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Answer:
V₂ = 0.98 L
Explanation:
Given data:
Initial volume = 750 mL =0.75 L
Initial pressure = 745 mmHg (745/760 =0.98 atm)
Initial temperature = 25 °C (25 +273 = 298 K)
Final temperature = -35°C (-35+273 = 238 K)
Final volume = ?
Final pressure = 0.60 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂/T₁ P₂
V₂ = 0.98 atm × 0.75 L × 238 K / 298 K × 0.60 atm
V₂ = 174.93 atm .L. K / 178.8 K.atm
V₂ = 0.98 L
Answer:
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In chemistry, orbital hybridisation (or hybridization) is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory.
Explanation:
