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Rudik [331]
3 years ago
13

M

Chemistry
2 answers:
finlep [7]3 years ago
7 0

Answer:

184N is my force wen carting a backpack

alexgriva [62]3 years ago
5 0

Answer:

183N

Explanation:

183N we have to add both mass

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Do gold and silver have the same extensive properties​
Pepsi [2]

Answer:

They do not

Explanation:

Gold is more advanced

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4 years ago
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What is the equation used to calculate average velocity
Nadya [2.5K]
Average velocity is the change in distance divided by the time it takes to travel that distance. so the first one.
6 0
3 years ago
What is the change in the freezing point of water when 68.5 g of sucrose is
mr Goodwill [35]
The change is that the water will freeze to 0 or minus I don’t know as I’m not to sure
7 0
4 years ago
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At what time will the pressure of SO₂Cl₂ decline to 0.50 its initial value? Express your answer using two significant figures.
QveST [7]

Answer: The time is 0.69/k seconds

Explanation:

The following integrated first order rate law

ln[SO₂Cl₂] - ln[SO₂Cl₂]₀ = - k×t

where

[SO₂Cl₂] concentration at time t,

[SO₂Cl₂]₀ initial concentration,

k rate constant

Therefore, the time elapsed after a certain concentration variation is given by:

t=\frac{ln[SO_{2}Cl_{2}]_{0} - ln[SO_{2}Cl_{2}]}{k}=\frac{ln\frac{[SO_{2}Cl_{2}]_{0}}{[SO_{2}Cl_{2}]} }{k}

We could assume that SO₂Cl₂ behaves as a ideal gas mixture so partial pressure is proportional to concentration:

p_{(SO_{2}Cl_{2})}V = n_{(SO_{2}Cl_{2})}RT

[SO_{2}Cl_{2}]= \frac{n_{(SO_{2}Cl_{2})}}{V}}=\frac{p_{(SO_{2}Cl_{2})}}{RT}}

In conclusion,

t = ln( p(SO₂Cl₂)₀/p(SO₂Cl₂) )/k

t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{p_{(SO_{2}Cl_{2})}} }{k}

for

p_{(SO_{2}Cl_{2})}=0.5p_{(SO_{2}Cl_{2})}_{0}

t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{0.5p_{(SO_{2}Cl_{2})_{0}}} }{k}

t=\frac{ln\frac{1}{0.5} }{k}

t=\frac{ln(2)}{k}

t=\frac{0.69}{k}}

7 0
3 years ago
Favorable (Exergonic) chemical reactions:
artcher [175]

Answer:

Usually give off heat energy

Explanation:

Exergonic reactions are the ones which are spontaneous. Spontaneous reactions are indicated by the negative change in the Gibbs free energy. In order to provide characteristics for an exergonic reaction, we need to define the Gibbs free energy in terms of the enthalpy change and the entropy change:

\Delta G=\Delta H-T\Delta S

Here:

\Delta H is the enthalpy change;

\Delta S is the entropy change;

T is the absolute temperature.

In order to achieve a negative value in the Gibbs free energy change, we should have:

\Delta H - T\Delta S

This is true for all temperatures if:

\Delta H < 0, \Delta S > 0

The major term here is the change in enthalpy, notice that we wish the enthalpy change to be negative.

Negative enthalpy change corresponds to an exothermic reaction, the one which releases heat. This means exergonic reactions would usually give off heat.

4 0
3 years ago
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