The final temperature of the sample of gas is 689.65 Kelvin.
<h3>What is the relation between temperature and pressure?</h3>
Relation between the temperature and pressure will be represented by the ideal gas equation PV = nRT, and for this question required equation is:
P₁/T₁ = P₂/T₂, where
P₁ & T₁ are the pressure and temperature of the initial sample.
P₂ & T₂ are the pressure and temperature of the final sample.
Pressure is in mmHg and on putting values from the question on the above equation, we get
T₂ = (810)(390.8) / (760) = 416.5 degree C = 689.65K
Hence required temperature of the sample is 689.65K.
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Answer:
375 K
Explanation:
Using the experssion shown below as:

At vaporization point, the liquid and the gaseous phase is in the equilibrium.
Thus,

So,

Given that:

Also, 1 kJ = 10³ J
So,


So, temperature is :


<u>T= 375 K</u>
Molecular is every element present in the compound eg C2H6, empirical is the smallest whole number ratio of elements in a compound so that would be CH3 as you divide by the highest common factor. Some compounds only have 1 formula if they are simple or have no common factors. Eg methane, CH4 is its molecular and empirical because its the simplest whole number ratio and includes every element in the molecule
Answer:
Mole ratio for a compound
The chemical formula tells us the mole ratio.
CO2 = 1 CO2 molecule : 1 C atom : 2 O atoms.
Mole ratio for a reaction
The balanced chemical reactions tells us.
C12H22O11 + 12 O2 12 CO2 + 11 H2O
1 C12H22O11 molecule: 12 O2 molecules : 12 CO2
molecules : 11 H2O molecules.
Applications of the mole ratio concept
grams <--> moles <--> moles <--> grams
Explanation: