Answer:
Explanation:
We shall find volume of gas at NTP or at 273 K , 760 mm of Hg .
Pressure of given gas = 1.06 x 760 mm of Hg less vapor pressure of water .
= 805.6 - 23.76 = 781.84 mm of Hg
For it we use gas law formula ,
P₁V₁ / T₁ = P₂V₂ / T₂
781.84 x 136.1 / ( 273 + 25 ) = 760 x V₂ / 273
= 128.26 mL .
= 128.26 x 10⁻³ L .
22.4 L of oxygen will have mass of 32 g
128.26 x 10⁻³ L of oxygen will have mass of 32 x 128.26 x 10⁻³ / 22.4 g
= 183.22 mg .
The ionic compound is CaSO4
Answer:
Igneous=B
Sedimentary=C
Metamorphic=A
Weathering is when=B
If sedimentary rock.....=C
1.062 mol/kg.
<em>Step 1</em>. Write the balanced equation for the neutralization.
MM = 204.22 40.00
KHC8H4O4 + NaOH → KNaC8H4O4 + H2O
<em>Step 2</em>. Calculate the moles of potassium hydrogen phthalate (KHP)
Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)
= 4.035 mmol KHP
<em>Step 3</em>. Calculate the moles of NaOH
Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)
= 4.035 mmol NaOH
<em>Step 4</em>. Calculate the mass of the NaOH
Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)
= 161 mg NaOH
<em>Step 5</em>. Calculate the mass of the water
Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g
= 37.973 g
<em>Step 6</em>. Calculate the molal concentration of the NaOH
<em>b</em> = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg
