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Goryan [66]
2 years ago
12

To dissolve one substance in another, thus forming a solution, three things must occur: The forces holding solute particles toge

ther must be broken. The forces holding solvent particles together must be broken. Attractions between solute and solvent particles must be formed.
Chemistry
1 answer:
aniked [119]2 years ago
4 0

To dissolve one substance, attractions between solute and solvent particles must be formed, steps involved are:

<h3><u>Formation of a solution:</u></h3>
  • A physical process, not a chemical one, takes place when a solute and a solvent combine to produce a solution.
  • In other words, by applying the right separation techniques, both the solute and the solvent may be recovered in chemically unaltered forms.
  • It is claimed that two substances are entirely miscible when they combine to create a single homogenous phase in all ratios. Water and ethanol mix well, much like different gas combinations do.
  • When two substances, like oil and water, are fundamentally insoluble in one another, they are said to be immiscible.
  • We have already talked about several examples of gaseous solutions, such as the atmosphere of Earth.
  • Thus, a system that has two or more compounds homogeneously (in a single phase) dissolved in it is called a solution. It is the homogenous mixture formed when a solute dissolves in a solvent.

To know more about solutions, refer to:

brainly.com/question/1616939

#SPJ4

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Answer:

Please, see attached two figures:

  • The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.

  • The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.

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Explanation:

The red  arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the <em>solubility</em> of <em>NH₄Cl.</em>

From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.

Assuming density 1.0 g/mol for water, 10 mL of water is:

            10mL\times 1.0g/mL=10g

Thus, the solutibily is:

      10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl

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