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Mekhanik [1.2K]
2 years ago
9

3. A chessboard is covered by 64 squares that are of the same size.

Mathematics
1 answer:
Paul [167]2 years ago
7 0
A is 8 because there has to be 8 squares on one side so the area is 64
B is equal to 32 squares because 8+8+8+8 is equal to 32
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Find the quotient.<br><br> 95<br> 92
Nostrana [21]

Answer:

1.033

Step-by-step explanation:

95

92     does not actually represent a quotient.  Write the quotient as

 95

------- = 1.033

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3 0
2 years ago
Is (6,-10) a solution of y=3x-8
Vitek1552 [10]
You can easily test this if you know that (6, -10) corresponds to (X, Y). Knowing this, you can: 

X = 6
Y = -10

you put this into your equation:

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calculate it:

-10 = 18 - 8
-10 = 10
This is not true of course, -10 is not equal to 10. Therefore, (6, -10) is not a solution of y = 3x-8 :)
6 0
3 years ago
Victor ran 6 miles on his first day of training the next day here and 1/6 that distance how far did he run the second day.
anastassius [24]
He ran 1 mile on the second day because 6÷6 =1
7 0
3 years ago
Read 2 more answers
Problem Set
insens350 [35]

5 liters (L) of 30% bleach solution contains 0.3×(5 L) = 1.5 L of bleach.

3 L of 50% bleach contains 0.5×(3 L) = 1.5 L of bleach, too.

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7 0
3 years ago
The roof of the Terminal Tower is 709 feet above ground. A window washer dropped a bucket from the edge of the roof. How many se
Masja [62]

Answer:

6.64 seconds

Step-by-step explanation:

Given that:

Distance between roof of the terminal and ground = 709 feet

A bucket was dropped from the roof.

To find:

The time taken by the bucket to hit the ground?

Solution:

Distance traveled, s = 709 feet

Initial velocity of the bucket, u = 0 feet/sec (because initially it was at rest)

Acceleration of the bucket will be equal to acceleration due to gravity i.e.

g or 32.1741 ft/sec^{2}

Let the time taken is t seconds.

Formula for distance is given as:

s = ut+\dfrac{1}{2}at^2

Putting all the values:

709 = 0 (t) + \dfrac{1}{2}(32.1741) t^2\\\Rightarrow 1418 = 32.1741 t^2\\\Rightarrow t^2 = 44.07\\\Rightarrow t \approx \bold{6.64\ sec}

6 0
2 years ago
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