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kobusy [5.1K]
3 years ago
13

Solving Exponential equation 7^7x+5 = 2^x-1

Mathematics
1 answer:
JulijaS [17]3 years ago
4 0

Answer:

x=-6/7^7-2

Step-by-step explanation:

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Choose three intervals on the real number line that contain both rational and irrational numbers. Do you think that any given in
Helen [10]

Any real number line ranges from negative infinity to positive infinity. A real number number line consists of all the rational and irrational numbers. Let us take three intervals which contain both the rational and irrational numbers.

First interval:  [3,4]

Since every integer is a rational number, 3 and 4 are both rational. In this interval there occurs the value of π (3.14159..) which is an irrational number.

Second interval :  [0,2]

0 and 2 are integers and hence are rational. In this interval, occurs √2 (1.41421...) is an irrational number.

Third interval : [2,3]

In this interval, Eulers number 'e' lie whose value is (2.718281.. )

Hence we can conclude that, there occurs an irrational number between any two rational number.

3 0
3 years ago
Eliminate the parameter in the equations x = 5cos(t) – 7 and y = 5sin(t) 9. how can the rectangular equation be described?
Maksim231197 [3]

Recall that for all t,

cos²(t) + sin²(t) = 1

Now,

x = 5 cos(t) - 7   ⇒   (x + 7)/5 = cos(t)

y = 5 sin(t) + 9   ⇒   (y - 9)/5 = sin(t)

so that substituting into the identity above, we get

((x + 7)/5)² + ((y - 9)/5)² = 1

which we can rewrite as

(x + 7)²/25 + (y - 9)²/25 = 1

(x + 7)² + (y - 9)² = 25

and this is the equation of a circle centered at (-7, 9) with radius 5.

3 0
2 years ago
Help:<br> <img src="https://tex.z-dn.net/?f=1.%5C%20%26x%5E4-61x%5E2%2B900%3D0%20%5C%5C%202.%20%5C%20%26%20x%5E4-25x%5E2%2B144%3
yawa3891 [41]

\bf{1) \  x^4-61x^2+900=0 }

Applying the factorization method, for example:

      \bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}

               \bf{\\ &=(x+6)(x-6)(x+5)(x-5);    }

              \bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5  }

\bf{2) \  x^4-25x^2+144=0  }

Applying the factorization method:

          \bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }

             \bf{ =(x-4)(x+4)(x-3)(x+3); }

            \bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3  }

7 0
2 years ago
Simplify the following expression: 9 – 3x + (-6x) + 4
natima [27]

Answer:

-9x + 13

Step-by-step explanation:

9 -3x +(-6x) +4

you will add -3x+(-6x), then add 9+4

-3x+(-6x) = -9x   (a negative pus and negative = a negative

9 +4 = 13

-9x + 13

8 0
2 years ago
List four numbers when counting backwards in steps of seven
morpeh [17]
28, 14, 7, 0 is a sequence for this
6 0
3 years ago
Read 2 more answers
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