Answer:
c it is not accelerating on it's on but gravity pulls it there for velocity increases.
To solve this problem we will use the definition of the kinematic equations of centrifugal motion, using the constants of the gravitational acceleration of the moon and the radius of this star.
Centrifugal acceleration is determined by

Where,
v = Velocity
r = Radius
From the given data of the moon we know that gravity there is equivalent to

While the radius of the moon is given by

If we rearrange the function to find the speed we will have to



The speed for this to happen is 1.7km/s
Answer:
The bullet that is fired will spend longer in the air, hitting the ground after the dropped bullet.
Explanation:
Using the equation: x
= x
0 +
v
t
If we neglect the effects of air resistance, the horizontal motion is a constant velocity.
The horizontal displacement = (velocity X cosθ)
So, the fired bullet has to travel horizontally before falling which takes a longer time compared to a bullet dropped where it is, height = 1/2 gt^2
gravity, g = 9.8 m/s2.