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il63 [147K]
3 years ago
12

What is the density of an object with the mass of 125g and a volume of 176 m

Physics
2 answers:
nordsb [41]3 years ago
7 0

Answer:

the density is mass over volume, so you divide 125g over 25 cm3, giving a result of 5 g/cm3

mars1129 [50]3 years ago
5 0

Answer:

The density is mass over volume

so you divide 125g over 25 cm3

giving a result of 5 g/cm3

you welcome have a good day!

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Nick and Mike are facing each other on skateboards. They touch palms and push off each other. Which best describes their movemen
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A word that would describe their movement would be force. the push is a force that keeps them away.
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You buy a magnifying glass at the store. The lens in the magnifying glass is a double convex lens, a lens with two convex curved
Leokris [45]

Answer:

30 cm

Explanation:

f = Focal length = 25 cm

R = Radius of curvature (both sides are equal)

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The lens maker formula is given by

\frac{1}{f}=(\mu-1)(\frac{1}{R_1}-\frac{1}{R_2})\\\Rightarrow \frac{1}{f}=(\mu-1)(\frac{1}{R}-\frac{1}{-R}) minus sign because it is on the other side

\\\Rightarrow \frac{1}{f}=(\mu-1)\frac{2}{R}\\\Rightarrow R=2(\mu-1)f\\\Rightarrow R=2(1.6-1)\times 25\\\Rightarrow R=30\ cm

The radius of curvature of the glass surface is 30 cm

8 0
4 years ago
With time running out in a game, Rachel runs towards the basket at a speed of 2.5 meters per second and from half-court, launche
finlep [7]

Answer:

Rachel(2.5,0)

ball(6.5,4.7)

b.R=10.15m/s, 27.57deg

Explanation:

The reference angle of Rachel is 00^{0} while the ball is at 36^{0}

resolving rachel's speed to the horizontal, we have

Ux=2.5cos0

Ux=2.5m/s

resolving rachel's speed to the vertical we have,

Uy=2.5sin0

Uy=0

for the ball

resolving the speed to its horizontal component

Ux=8cos36

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Uy=8sin36

Uy=4.7m/s

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ball(6.5,4.7)

To get the resultant of their speed

Add the horizontal speed of rachel to that of the ball to get the total horizontal speed

Add the vertical speed of rachel and the ball to get the total vertical speed component

TUx=2.5+6.5=9M/S

TUy=0+4.7=4.7m/s

R=\sqrt{(TUx^2+TUy^2}

R=\sqrt{(9^2+4.7^2}

R=\sqrt{(103)}

R=10.15m/s

the direction

tan\alpha=TUy/TUx

tan\alpha=4.7/9

\alpha=tan^-1(0.522)

\alpha=27.57deg

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