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Deffense [45]
4 years ago
6

A 0.060 kg ball hits the ground with a speed of -32m/s. The ball is in contact with the ground for 45 milliseconds and the groun

d exerts a +55 N force on the ball. What is the magnitude of the velocity after it hits the ground?
A. 9.3m/s
B.12m/s
C.41m/s
D.73m/s
Physics
2 answers:
Dominik [7]4 years ago
9 0
Using the kinematic equation V=Vo + at, the initial velocity (Vo) is -32, the acceleration (a) is found by dividing force by mass 55N/.06kg=916.66 m/s/s, and the time is 0.045 sec.

V=Vo+at
V=-32+916.66*.045
V=9.25

The answer is A.
aleksklad [387]4 years ago
7 0

it's A. i took the test right now

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Find the wavelength λ of the 80.0-khz wave emitted by the bat. express your answer in millimeters.
vfiekz [6]

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4 0
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Three children are riding on the edge of a merry-go-round that is 100 kg, has a 1.60-m radius, and is spinning at 20.0 rpm. The
Kay [80]

Answer:

25.33 rpm

Explanation:

M = 100 kg

m1 = 22 kg

m2 = 28 kg

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r = 1.60 m

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Let the new angular speed in rpm is f'.

According to the law of conservation of angular momentum, when no external torque is applied, then the angular momentum of the system remains constant.

Initial angular momentum = final angular momentum

(1/2 x M x r^2 + m1 x r^2 + m2 x r^2 + m3 x r^2) x ω =

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2660 = 105 x f'

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8 0
3 years ago
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