Answer:
The magnitude of the magnetic flux through the loop is 0.0982 T.m²
Explanation:
Given;
magnitude of magnetic field, B = 0.5 T
radius of the loop, r = 0.25 m
Area of the loop is given by;
A = πr²
A = 3.142 x (0.25)²
A = 0.1964 m²
The magnitude of the magnetic flux through the loop is given by;
Ф = BA
Where;
B is the magnitude of the magnetic field
A is area of the field
Ф = 0.5 x 0.1964
Ф = 0.0982 T.m²
Therefore, the magnitude of the magnetic flux through the loop is 0.0982 T.m²
Answer:
20.3N
Explanation:
Given parameters:
Area of the eardrum = 0.0002m²
Pressure on the eardrum = 1atm = 101325Nm⁻²
Unknown:
Force exerted on the eardrum = ?
Solution:
Pressure is the force per unit area impacted on a body.
Pressure =
Force = Pressure x area
Now insert the parameters and solve;
Force = 101325Nm⁻² x 0.0002m² = 20.3N
First we will find the speed of the ball just before it will hit the floor
so in order to find the speed of the cart we will first use energy conservation



So by solving above equation we will have

now in order to find the momentum we can use


