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Natasha_Volkova [10]
3 years ago
7

Starting at the same time, an arrow and a ball are shot horizontally with a speeds of 50 m/s and 44 m/s respectively from the to

p of a building over flat ground. Which best describes what happens? A. The arrow and the ball land the same distance from the building at different times. B. The arrow and the ball land at different distances from the building at different times. C. The arrow and the ball land the same distance from the building at the same time. D. The arrow and the ball land at different distances from the building at the same time.
Physics
1 answer:
Yuri [45]3 years ago
5 0

Answer:

option D

Explanation:

given.

horizontal velocity of arrow and a ball given as  50 m/s and 44 m/s respectively from the top of a building over flat ground.

In vertical direction, they are both identical

In vertical direction the initial velocity of arrow and a ball  is 0  m/s

Their acceleration due to gravity  is same for both arrow and a ball  9.8 m/s²

they will react bottom at the same time

 time of flight is same for both

now,

In horizontal direction,

distance = speed × time

Since speed is more for arrow, it will travel more horizontal distance  at the same time.

the correct answer is option D

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The electric potential in a certain region varies with position as V(x) = ax2 - bx + c, where a = 2.2 V/m2, b = 16.5 V/m, and c
Effectus [21]

Answer:

idk it its A

Explanation:

i did it

6 0
3 years ago
A 0.50-T magnetic field is directed perpendicular to the plane of a circular loop of radius 0.25 m. What is the magnitude of the
Cloud [144]

Answer:

The magnitude of the magnetic flux through the loop is 0.0982 T.m²

Explanation:

Given;

magnitude of magnetic field, B = 0.5 T

radius of the loop, r = 0.25 m

Area of the loop is given by;

A = πr²

A = 3.142 x (0.25)²

A = 0.1964 m²

The magnitude of the magnetic flux through the loop is given by;

Ф = BA

Where;

B is the magnitude of the magnetic field

A is area of the field

Ф = 0.5 x 0.1964

Ф = 0.0982 T.m²

Therefore, the magnitude of the magnetic flux through the loop is 0.0982 T.m²

6 0
3 years ago
a persons eardrum has an area of 0.000200 m^2. How much force does the outside air at 1.00 atm exert on the eardrum
alexdok [17]

Answer:

20.3N

Explanation:

Given parameters:

Area of the eardrum  = 0.0002m²

Pressure on the eardrum  = 1atm  = 101325Nm⁻²

Unknown:

Force exerted on the eardrum  = ?

Solution:

Pressure is the force per unit area impacted on a body.

      Pressure  = \frac{Force }{area}  

  Force  = Pressure x  area

Now insert the parameters and solve;

  Force  =  101325Nm⁻²  x  0.0002m²  = 20.3N

5 0
3 years ago
A ball, which has a mass of 1.25 kg, is thrown straight up from the top of a building 225 meters tall with a velocity of 52.0 m/
Anastasy [175]

First we will find the speed of the ball just before it will hit the floor

so in order to find the speed of the cart we will first use energy conservation

KE_i + PE_i = KE_f + PE_f

\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv_f^2 + 0

\frac{1}{2}(1.25)(52)^2 + 1.25(9.8)(225) = \frac{1}{2}(1.25)v_f^2

So by solving above equation we will have

v_f = 84.3 m/s

now in order to find the momentum we can use

P = mv

P = 1.25 \times 84.3

P = 105.4 kg m/s

3 0
4 years ago
if air resistance is negligible what maximum height will be reached by a stone thrown straight up with an initial speed of 35 m/
alexandr1967 [171]
I think it will be 61.25 m
6 0
4 years ago
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