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Alekssandra [29.7K]
2 years ago
9

Is facilitated diffusion passive or active transport?

Chemistry
1 answer:
bazaltina [42]2 years ago
6 0

Answer:

Its passive

Explanation:

Facilitated diffusion is a type of passive transport that allows substances to cross membranes with the assistance of special transport proteins.

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What volume (in liters) of a solution contains 0.14 mol of KCl?
oksano4ka [1.4K]

Answer:

\boxed {\boxed {\sf 0.078 \ L }}

Explanation:

We are asked to find the volume of a solution given the moles of solute and molarity.

Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:

molarity= \frac{moles \ of \ solute}{liters \ of \ solution}

We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.

  • moles of solute = 0.14 mol KCl
  • molarity= 1.8 mol KCl/ L
  • liters of solution=x

Substitute these values/variables into the formula.

1.8 \ mol \ KCl/ L = \frac { 0.14 \ mol \ KCl}{x}

We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

\frac {1.8 \ mol \ KCl/L}{1} = \frac{0.14 \ mol \ KCl}{x}

1.8 \ mol \ KCl/ L *x = 1*0.14 \ mol \ KCl

1.8 \ mol \ KCl/ L *x = 0.14 \ mol \ KCl

Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.

\frac {1.8 \ mol \ KCl/ L *x}{1.8 \ mol \ KCl/L} = \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}

x= \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}

The units of moles of potassium chloride cancel.

x= \frac{0.14 }{1.8 L}

x=0.07777777778 \ L

The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.

x \approx 0.078 \ L

There are approximately <u>0.078 liters of solution.</u>

5 0
2 years ago
Does the amount of a substance affect the properties of a substance?
Veseljchak [2.6K]
No, the properties of a substance are not affected by the amount of a substance.
5 0
3 years ago
How many grams of KCIO3 will be formed from 3.58g of KCI
blsea [12.9K]

Answer:

5 mols

Explanation:

7 0
2 years ago
How to solve 2 and 3
GarryVolchara [31]
Use the Heat formula for both problems.

q=m*c*∆t

Where
q= heat in Joules
m= mass in grams
c= specific heat which is a constant 4.18
∆t= change in temperature
3 0
3 years ago
When .50 mL of 2.0M Li3PO4 is added to 50 mL of 1.0 M LiH2PO4 what is the resulting concentration of Li+?
jeka57 [31]
Hence the resulting concentration of Li+ is 1M. Hope it helps.

8 0
3 years ago
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