Answer: P= 1.64 atm
Explanation: solution attached.
Use Ideal gas law
PV= nRT
Derive for P
P= nRT/V R= 0.08205 L.atm/mol.K
Substitute the values.
Answer:
(R)-but-3-en-2-ylbenzene
Explanation:
In this reaction, we have a very <u>strong base</u> (<em>sodium ethoxide</em>). This base, will remove a hydrogen producing a double bond. We know that the reaction occurs through an <u>E2 mechanism</u>, therefore, the hydrogen that is removed must have an <u>angle of 180º</u> with respect to the leaving group (the "OH"). This is known as the <u>anti-periplanar configuration</u>.
The hydrogen that has this configuration is the one that placed with the <u>dashed bond</u> (<em>red hydrogen</em>). In such a way, that the base will remove this hydrogen, the "OH" will leave the molecule and a double bond will be formed between the methyl and the carbon that was previously attached to the "OH", producing the molecule (R) -but-3- en-2-ylbenzene.
See figure 1
I hope it helps!
Answer:Increased the number of molecular collisions and increased the reaction rate
Explanation:
Answer:
Time of vaporization = 0.588 minutes
Explanation:
The latent heat of fusion is the heat required to change the substance from solid (ice) to liquid completely, without further increase in temperature.
The latent heat of vaporization is the heat required to change a liquid to gas completely, without an increase in temperature.
Latent heat of vaporization = 6.8 times Latent heat of fusion
This means that the time it takes for the latent heat of vaporization to complete vaporization is 6.8 times lesser than the time it takes for the latent heat of fusion to complete fusion
Time of vaporization = 6.8 times lesser than time of fusion
Time of vaporization = (time of fusion) ÷ 6.8
where: Time of fusion = 4 minutes
∴ Time of vaporization = 4 ÷ 6.8
Time of vaporization = 0.588 minutes