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kotykmax [81]
3 years ago
15

HOLMIUM

Chemistry
1 answer:
Sophie [7]3 years ago
8 0

Answer:

1. The graph where x axis and y axis are present is called coordinate.

4. 18

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How many protons, electrons, and neutrons does the following isotope contain?<br> 27 A13+
Lapatulllka [165]

Hey there!

27 tells us the sum of protons and neutrons is 27.

Al tells us we have 13 protons.

3+ tells us that there are 3 less electrons than protons.

13 + n = 27

neutrons = 14

13 - 3 = 10 electrons

27Al3+ has 13 protons, 14 neutrons, and 10 electrons.

Hope this helps!

7 0
3 years ago
The decomposition of N2O4 into NO2 has Kp = 2. Some N2O4 is placed into an empty container, and the partial pressure of NO2 at e
Sunny_sXe [5.5K]

Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

           N_{2}O_{4} \rightarrow 2NO_{2}

Let us assume that x concentration of N_{2}O_{4} is present at the initial stage. Therefore, according to the ICE table,

                    N_{2}O_{4} \rightarrow 2NO_{2}

Initial :               x                   0

Change :       - 0.1        2 \times 0.1

Equilibrium : (x - 0.1)             0.2

Now, expression for K_{p} of this reaction is as follows.

     K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

Putting the given values into the above formula as follows.

          K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

                 2 = \frac{(0.2)^{2}}{(x - 0.1)}

                2 \times (x - 0.1) = (0.2)^{2}

                            x = 0.12

This means that P_{N_{2}O_{4}} = x = 0.12 atm.

Thus, we can conclude that the initial pressure in the container prior to decomposition is 0.12 atm.

6 0
3 years ago
What volume of 0.128 M HCl is needed to neutralize 2.87 G of Mg(OH)2?
qaws [65]
V= .768L= 76.8ml HCL
4 0
3 years ago
The maximum oxygen uptake is known as the __________.
andrezito [222]
The maximum oxygen uptake is known as the VO2 max.
4 0
3 years ago
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A biology student set up an experiment to study 9 mice. On day 1, they were measured for weight and length. Then the mice were p
Sophie [7]
The independent variable would be the variable in the research that is being manipulated by the researcher. In this case, it would be temperature in the cage as it is what is being manipulated and changed in the research design. The dependent variable would be the variable that is being studied so, for this case, it would be the length and the weight of the mice. The constants are the factors that might affect the dependent variable but is held constant or the same by the researcher throughout the experiment. These are the size of the cage, amount of food and the exercise wheel. The flaw that the scientist would be studying the length of the mice since I don't think the temperature has any effect on it. And base from he results, the change in lengths are not conclusive.
4 0
3 years ago
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