3 years ago

HOLMIUM

Chemistry

1 answer:

Sophie [7]3 years ago

8 0

Answer:

1. The graph where x axis and y axis are present is called coordinate.

4. 18

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How many mm are in 5 m

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1 meter = 1000mm

* 5

5 meters = 5000mm

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3 years ago

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If the daily allowance for Vitamin C is assumed to be 75.0 mg, how many liters (L) of a 0.002486 M solution of ascorbic acid wou

kati45 [8]

Answer:

Volumen C6H8O6(sln) = 2.569 L ≅ 2.6 L

Explanation:

vitamin C ≡ ascorbic acid (C6H8O6)

∴ vitamin C/daily = 75.0 mg/d

∴ molar mass C6H8O6 = 176.12 g/mol

solution:

∴ <em>C</em> C6H8O6 = 0.002486 mol/L

⇒ ppm C6H8O6 = (0.002486 mol/L)*(176.12 g/mol)*(1000 mg/g)

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for a 15.0 day:

⇒ Volume C6H8O6(sln) = (75.0 mg/d)*(L/437.834 mg)*(15.0 d)

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3 years ago

Which statement is the best description of a chemical reaction? the decomposition of particles the combustion of a substance for

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The combustion of a substance forming or breaking bonds mixing two substances.

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3 years ago

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How is data not actually obtained from the experiment represented in a line graph?

vfiekz [6]

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4 years ago

Read the statement.

lina2011 [118]

Answer:

60 g/L is the final concentration of NaI solution .

Explanation:

Molarity of NaI solution before evaporation = $M_1= 0.2 M$

Volume of NaI solution before evaporation = $V_1= 2.0 L$

Molarity of NaI solution after evaporation = $M_2= ?$

Volume of NaI solution after evaporation = $V_2= 1.0 L$

$M_1V_1=M_2V_2$ ( dilution)

$M_2=\frac{M_1V_1}{V_2}=\frac{0.2 M\times 2.0 L}{1.0 L}=0.4 M$

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Concentration of NaI after evaporation :

0.4 M × 150 g/mol = 60 g/L

60 g/L is the final concentration of NaI solution .

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3 years ago