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Alexandra [31]
3 years ago
11

an object of 30kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.

Physics
1 answer:
Ivan3 years ago
4 0

We're missing one essential piece of information that we need in order to answer this question.  You have not specified <em>what planet</em> the object is falling on.  The answer depends on the gravitational acceleration on that planet, and they're all different.

Without that information, we'll just go ahead and assume that the object is falling to the surface of the Earth.  Wherever on Earth this tense drama is unfolding, the acceleration of gravity is going to be around <em>9.8 m/s²</em> everywhere.

So THAT's the object's acceleration if there is no air resistance.  The object's MASS makes no difference.  It doesn't matter whether the object is a sparrow feather or a school bus. Heavier objects DO NOT fall faster than light objects.

If there is no air resistance, then ALL objects fall with the same acceleration.    It's called the "acceleration of gravity" on that planet or moon, and you can easily look it up.  It's 9.8 m/s² on Earth, 1.62 m/s² on the Moon, 3.71 m/s² on Mars, 8.87 m/s² on Venus, and 24.8 m/s² on Jupiter.

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If each washer has a mass of 4.9 g, then the mass of two washers in kilograms would be Given that F = ma, and if 4 washers are a
zysi [14]

Given that,

Mass of each washer  = 4.9 g

We need to calculate the mass of two washers in kg

Using conversion of unit

Mass of each washer m= 4.9\times10^{-3}\ Kg

So, Mass of two washers is

M=2\times m

Put the value of m

M=2\times4.9\times10^{-3}\ k

M=0.0098\ Kg

If 4 washer are attached to the spring

We need to calculate the applied force on the car

Using formula of force

F=mg

Put the value into the formula

F=4\times4.9\times10^{-3}\times9.8

F=0.192\ N

Hence, (i), The mass of two washers is 0.0098 kg.

(ii). The applied force on the car is 0.192 N.

6 0
3 years ago
A car is stopped at a traffic light. It then travels along a straight road so that its distance from the light is given by x(t)=
True [87]

Answer:

(a) average velocity = 17.6 m/s

(b) when t = 0, v = 0

    when t = 4, v = 19.2 m/s

    when t = 8, v = 28.8 m/s

(c) after starting from rest, the car will be at rest again in 20 s

Explanation:

Given;

x(t)=bt²−ct³, substitute the given values and the equation will become;

x(t)=3t²−0.1t³

(a)average velocity = total distance / total time

total distance, x(t) = 3t²−0.1t³

x(8) = 3t²−0.1t³

X(8) = 3(8)² - 0.1(8)³

X(8) = 140.8 m

total time = 8 s

average velocity = 140.8 / 8

average velocity = 17.6 m/s

(b) instantaneous velocity = dx / dt

dx / dt = 6t - 0.3t²

when t = 0

v = 0

when t = 4 s

v = 6(4) - 0.3(4²) = 19.2 m/s

when t = 8 s

v = 6(8) - 0.3(8²) = 28.8 m/s

(c) the velocity is zero at dx / dt = 0

6t - 0.3t² = 0

t(6 - 0.3t) = 0

t = 0    or  6 - 0.3t = 0

t = 0     or   0.3t = 6

t = 0      or   t = 6 / 0.3

t= 0       or    t =  20 s

After starting from rest, the car will be at rest again in 20 s

6 0
3 years ago
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