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Alexandra [31]
3 years ago
11

an object of 30kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.

Physics
1 answer:
Ivan3 years ago
4 0

We're missing one essential piece of information that we need in order to answer this question.  You have not specified <em>what planet</em> the object is falling on.  The answer depends on the gravitational acceleration on that planet, and they're all different.

Without that information, we'll just go ahead and assume that the object is falling to the surface of the Earth.  Wherever on Earth this tense drama is unfolding, the acceleration of gravity is going to be around <em>9.8 m/s²</em> everywhere.

So THAT's the object's acceleration if there is no air resistance.  The object's MASS makes no difference.  It doesn't matter whether the object is a sparrow feather or a school bus. Heavier objects DO NOT fall faster than light objects.

If there is no air resistance, then ALL objects fall with the same acceleration.    It's called the "acceleration of gravity" on that planet or moon, and you can easily look it up.  It's 9.8 m/s² on Earth, 1.62 m/s² on the Moon, 3.71 m/s² on Mars, 8.87 m/s² on Venus, and 24.8 m/s² on Jupiter.

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The 2 roles of forensic engineers is the detective role and then the engineering role.
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3 years ago
The average radial velocity of galaxies in the Hercules cluster is 10,800 km/s. (a) using H0 = 73 km/s/Mpc, find the distance to
ArbitrLikvidat [17]

Answer:

a) 147.95 Mpc

Explanation:

Using Hubble's formula

v = H_od

where;

v = radical velocity

H_o = Hubble's constant

d = distance

Given that:

The average radial velocity of galaxies in the Hercules cluster v =  10,800 km/s

Also using H_o = 73 km/s/ Mpc ; we  make distance d the subject of the formula:

Then distance d can be written as:

d = \frac{v}{H_o}

d = \frac{10,800  \ km/s}{73 \ km/s/Mpc}

d = 147.95 Mpc

b)

Now, if the Hubble constant had a smaller value, then for a  given velocity the distance to the galaxy will increase because distance d is inversely proportional to H_o

i.e  

d  ∝ \frac{1}{H_0}

4 0
3 years ago
Trong thí nghiệm giao thoa trên mặt nước, hai nguồn kết hợp A và B cách nhau 32 cm dao động cùng
antiseptic1488 [7]

Answer:

48cm by the minus of difference of 32 CM length 20 CM because of the length of the building

5 0
2 years ago
A rose plant inherited two alleles for white flower petals.
Alik [6]

Answer:

a

Explanation:

5 0
3 years ago
Read 2 more answers
A simple generator is used to generate a peak output voltage of 19.0 V . The square armature consists of windings that are 6.65
salantis [7]

One of the efficient concepts that can help us find the number of turns of the cable is through the concept of induced voltage or electromotive force given by Faraday's law. The electromotive force or emf can be described as,

\epsilon = NBA\omega

Where,

N = Number of loops

B = Magnetic Field

A = Cross-sectional Area

\omega = Angular velocity

Re-arrange to find N,

N = \frac{\epsilon}{BA\omega}

Our values are given as,

\epsilon = 19V

B = 0.434T

\omega = 49.8\frac{rev}{s} (\frac{2\pi rad}{1 rev}) = 99.6\pi rad/s

A = (6.65*10^{-2})^2 m^2

Replacing at our equation we have:

N = \frac{\epsilon}{( 0.434)A\omega}

N = \frac{19}{( 0.434)((6.65*10^{-2})^2)(99.6\pi)}

N = 31.63 \approx 32

Therefore the number of loops of wire should be wound on the square armature is 32 loops

6 0
3 years ago
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