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Alexandra [31]
3 years ago
11

an object of 30kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.

Physics
1 answer:
Ivan3 years ago
4 0

We're missing one essential piece of information that we need in order to answer this question.  You have not specified <em>what planet</em> the object is falling on.  The answer depends on the gravitational acceleration on that planet, and they're all different.

Without that information, we'll just go ahead and assume that the object is falling to the surface of the Earth.  Wherever on Earth this tense drama is unfolding, the acceleration of gravity is going to be around <em>9.8 m/s²</em> everywhere.

So THAT's the object's acceleration if there is no air resistance.  The object's MASS makes no difference.  It doesn't matter whether the object is a sparrow feather or a school bus. Heavier objects DO NOT fall faster than light objects.

If there is no air resistance, then ALL objects fall with the same acceleration.    It's called the "acceleration of gravity" on that planet or moon, and you can easily look it up.  It's 9.8 m/s² on Earth, 1.62 m/s² on the Moon, 3.71 m/s² on Mars, 8.87 m/s² on Venus, and 24.8 m/s² on Jupiter.

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Explain how you find the density of a liquid subtance example corn syrup
STatiana [176]
Use the density formula:

Mass of the substance
————————————
Volume of the substance

This gives you the density.


Corn syrup has a density of about 1.4 grams per cubic centimeter, and has the highest density of all liquids!

Hope this helps!
3 0
3 years ago
"Videos of hoverboard riders who were injured when they fell while operating their hoverboards at a low speeds "went viral" over
bagirrra123 [75]

Answer:

The answer is "No, Hoverboards are risky, and riders are in danger of falling".

Explanation:

It's also known as a self-balanced scooter, it handheld electrical devices traveling on two wheels are hoverboards. It dominated the industry around 2015 and since then has become more and more successful. A rider is balanced on a frame between these wheels, driven by battery-powered lithium-ion batteries.

8 0
3 years ago
A 57 g ice cube can slide without friction up and down a 33 ∘ slope. The ice cube is pressed against a spring at the bottom of t
beks73 [17]
The springs stored energy is transferred to the cube as kinetic energy and then by the slop the KE is converted to height energy. 

<span>0.5 . k . x^2 = 0.5 . m . v^2 = m . g . ∆h </span>

<span>0.5 . 50 . (0.1^2) = 0.05 . 9.8 . ∆h </span>

<span>∆h = 0.51 m = 51 cm </span>

<span>This is the height gained </span>
<span>Distance along the slope = ∆h / sin 60 = 0.589 = 59 cm </span>

<span>In the second case, the stored spring energy is converted into height energy AND frictional heat energy. </span>

<span>The height energy is m . g . d sin 60 where d is the distance the cube moves along the slope. </span>

<span>The Frictional energy converted is F . d </span>

<span>F ( the frictional force ) = µ . N </span>

<span>N ( the reaction to the component of the gravity force perpendicular to the surface of the slope ) = m . g . cos60 </span>

<span>Total energy converted </span>

<span>0.5 . k . x^2 = (m . g . dsin60) + (µ . m . g . cos60 . d ) </span>

<span>Solve for d </span>

<span>d = 0.528 = 53 cm</span>
5 0
3 years ago
If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front o
Svetach [21]
C.
18 / x = 12 / 4
12x = 72
x = 6mm
6 0
3 years ago
A student pushes a 12.0 kg box with a horizontal force of 20 N. The friction force on the box is 9.0 N. Which of the following i
Hoochie [10]

The acceleration of the box is approximately 1 m/s^2

Explanation:

According to Newton's second law of motion, the net force acting on the box is equal to the product between its mass and its acceleration:

\sum F = ma

where

\sum F is the net force

m = 12.0 kg is the mass of the box

a is the acceleration

The net force can be written as

\sum F = F_a - F_f

where

F_a = 20 N is the applied forward force

F_f=9.0 N is the friction force

Combining the two equations,

F_a-F_f=ma

And solving for the acceleration,

a=\frac{F_a-F_f}{m}=\frac{20-9}{12}=0.9 m/s^2\sim 1 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

8 0
3 years ago
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