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andrew11 [14]
3 years ago
7

For a snowboard jumper in the air, what force or forces will be most important for modeling the motion?

Physics
1 answer:
Reptile [31]3 years ago
4 0

Answer: Gravitational force and drag force

Explanation:

For a snowboard jumper in the air, two forces would be acting. One in the downward direction- the gravitational pull and second in the opposite direction to the motion, the drag force due to air. If the snowboard jumper jumps in the air at a certain angle with the horizontal. The forces are written as the sum of vertical and horizontal components. Hence, for the modeling the motion, gravitational force and drag force are important,

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the power of a physicians eyes is 57.1 D while examinging a patient. how far from her eyes (in m) is the feature being examined.
yanalaym [24]

Answer:

14 cm

Explanation:

Power of eye = 57.1 D

The relation between the focal length and the power is

f = 1 / P = 1 / 57.1 = 0.0175 m = 1.75 cm

The distance between the image and the lens is, v = 2 cm

Let the distance between the object and the eye is u

Use the lens equation

1/ f = 1 / v - 1 / u

1 / 1.75 = 1 / 2 - 1 / u

1 / u = 1 / 2 - 1 / 1.75

1 / u = (1.75 - 2) / 3.5

u = - 14 cm

Thus, the distance between the feature and eye is 14 cm .

8 0
3 years ago
5. YOU SHOULD USUALLY DRIVE SLOWER
saveliy_v [14]

Answer:

The answer is C.

Explanation:

If there are brake lights then you should drive slower.

3 0
3 years ago
Read 2 more answers
A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of
Leto [7]

Answer: 2.27\ m/s^2

Explanation:

Given

Length of the race track L=200\ m

the radius of curvature of the track r=29.5\ m

time taken to run on track is t=24.4\ s

Speed of runner is

\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s

Centripetal acceleration is

\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2

5 0
3 years ago
A holiday ornament in the shape of a hollow sphere with mass 0.015 kg and radius 0.055 m is hung from a tree limb by a small loo
s344n2d4d5 [400]

Answer: 0.61 s

Explanation:

Given

Mass of object, m = 0.015 kg

Radius of object, r = 0.055 m

Acceleration of object, g = 9.8 m/s²

In a pendulum,

T = 2π * √[I /(mgd)]

The moment of Inertia, I of a hollow sphere is given by

I(sphere) = 2/3MR² + MR²

I(sphere) = 5/3MR²

Also, d = R

Substituting these into the first equation, we have

T = 2π * √[(5/3MR²) / (mgr)]

T = 2π * √[(5/3r) / (g)]

T = 2 * 3.142 * √(5/3 * 0.055) / (9.8)]

T = 6.284 * √(0.092/9.8)

T = 6.284 * √0.00939

T = 6.284 * 0.097

T = 0.6095 s

To 2 significant figures,

The period is 0.61 s

7 0
3 years ago
A 1627 kg car moves with a velocity of 16 m/s. What is its kinetic energy?
TEA [102]
Kinetic Energy = (1/2)mv² = 0.5×1627×16² = 208256J
7 0
4 years ago
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