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lana66690 [7]
3 years ago
6

Inverse beta decay, the subatomic interaction by which an electron and a proton are "crushed" into a neutron, the process in whi

ch the recoil, on a massive scale of an entire stellar nucleus, pushes out the outer layers of the star in the cataclysmic explosion of a supernova and transforms the stellar nucleus into a neutron star.
Physics
1 answer:
gogolik [260]3 years ago
5 0

Options:

A. the process in which the recoil, on a massive scale of an entire stellar nucleus, pushes out the outer layers of the star in the cataclysmic explosion of a supernova and transforming

B. the process where the recoil, on a massive scale of an entire stellar nucleus, are pushing out the outer layers of the star in the cataclysmic explosion of a supernova and transforms

C. the process in which the recoil, on a massive scale of an entire stellar nucleus, pushes out the outer layers of the star in the cataclysmic explosion of a supernova and are transforming

D. is the process in which the recoil, on a massive scale of an entire stellar nucleus, pushes out the outer layers of the star in the cataclysmic explosion of a supernova and transforms

E. is the process where the recoil, on a massive scale of an entire stellar nucleus, are pushing out the outer layers of the star in the cataclysmic explosion of a supernova and transforms

Answer:

D. is the process in which the recoil, on a massive scale of an entire stellar nucleus, pushes out the outer layers of the star in the cataclysmic explosion of a supernova and transforms

Explanation:

NB: In options A-C, the verb "is" is required as a compliment to the subject "inverse beta decay"

The tenses used also do not align with the subjects.

Option E uses "where" for a process. This is wrong, it should only be used for a physical location

Only option D does not violate any rule of concord.

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Refer to the diagram shown below.

For horizontal equilibrium,
T₃ cos38 = T₂ cos 50
0.788 T₃ = 0.6428 T₂
T₃ = 0.8157 T₂                (1)

For vertical equilibrium,
T₂ sin 50 + T₃ sin 38 = 430
0.766 T₂ + 0.6157 T₃ = 430
1.2441 T₂ + T₃ = 698.392        (2)

Substitute (1) into (2).
(1.2441 + 0.8157) T₂ = 698.392
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A spring 1.50 m long with force constant 448 N/m is hung from the ceiling of an elevator, and a block of mass 10.9 kg is attache
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Answer:

Explanation:

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Answer:

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then add them: = 151/1365

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