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vichka [17]
3 years ago
7

A car engine burns gas at 495 K, and exhausts to the air at 293 K. If it ran at the highest possible efficiency, how much input

heat would it take to do 10,000 J of work? (Unit=J)
Physics
1 answer:
slamgirl [31]3 years ago
4 0

  The heat taken to do the 10,000 J of work is 4081 J

<u>Explanation:</u>

The ratio of the temperature difference between the reservoirs and the temperature of the hot reservoir is termed as maximum thermal efficiency.

Maximum thermal efficiency is

                                                   1 - (Tc / Th).

where Tc represents the  absolute temperature of the cold reservoir

           Th represents the absolute temperature of the hot reservoir.

                                                    1 - (293/495) = 0.408  

If the input is 10,000 J, then 4081 J is used to do work.  The remaining 5919 J is rejected as heat into the air.

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5 0
3 years ago
What is the power through a device with a resistance of 100 ohms if a current of 8 A is running through it?
Kazeer [188]

Answer:

6400 W (or) 6.4 KW

Explanation:

Formula we use,

→ P = I²R

Let's solve for the power of device,

→ P = I²R

→ P = (8)² × 100

→ P = 64 × 100

→ [ P = 6400 W ]

Hence, the power is 6400 W.

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2 years ago
Which sphere of Earth do humans exist in?
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4 0
3 years ago
Read 2 more answers
The granulation pattern that astronomers have observed on the surface of the Sun tells us that: a. the Sun is a lot cooler on th
Norma-Jean [14]

Answer:

c. hot material must be rising from the Sun's hotter interior

Explanation:

Granulation is the grainy appearance of the solar photosphere produced by the top of the convection cells in the sun.

The grainy appearance are produced by granules on the photosphere of the sun and granules are caused by convection currents of plasma within the sun's convection zone.

The interior of these granules are brighter (and thus hotter) than the exterior of the granules which are darker.

<u>So, the granulation pattern that astronomers have observed on the surface of the Sun tells us that hot material must be rising from the Sun's hotter interior.</u>

4 0
3 years ago
An object is thrown upward from the edge of a tall building with a velocity of 10 m/s. Where will the object be 3 s after it is
Alik [6]
We use a fundamental kinematic equation as follows:

V = Vo + g*t. 
<span>Tr = (V-Vo)/g = (0-10)/-10 = 1 s. = </span><span>time to reach max. height </span>

<span>Tf = Tr = 1 s. = Fall time or time to fall back to edge of bldg. </span>

<span>3-Tr-Tf = 3-1-1 = 1 s. Below edge of bldg. </span>

<span>d = Vo*t + 0.5g*t^2. </span>
<span>d = 10*1 + 5*1^2 = 15 m. <---- OPTION C</span>
8 0
3 years ago
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