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lidiya [134]
1 year ago
12

1. Predict whether the energy required to remove an electron from magnesium and potassium would be more or less than that requir

ed to remove an electron from sodium. Explain your prediction in terms of the forces and interactions involved in this process. \
FILL OUT THE TABLE PLEASE WITH A GOOD ANSWER FOR BRAINLIEST!

Physics
1 answer:
Inga [223]1 year ago
8 0

In both cases less energy is required

But comparetively Mg require more energy than K

Let's see the electron configuration of Both

  • [Mg]=1s²2s²2p⁶3s²=[Ne]3s²
  • [K]=1s²2s²2p⁶3s²3p⁶4s¹=[Ar]4s¹

K has only one valence electron so very less ionization enthalpy so less energy required

Mg has 2 so more IE hence more energy required

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uysha [10]

Answer:The sled slides 16.875m before rest.

Explanation:

a=\frac{F}{m} =\frac{12N}{20kg}

a=0.6 m/s²

Vf=0=Vi-a.t

t=\frac{Vi}{a} =t=\frac{4.5m/s}{0.6 m/s2} =t=7.5seg

d= Vi.t - \frac{a.t^{2}}{2}

d= 4.5 * 7.5 - \frac{0.6*7.5^{2} }{2} \\\\d=16.875m

3 0
3 years ago
Help when u can! I feel like it's C, but I just want to make sure before I submit the test.
Marat540 [252]

(D)

Explanation:

This kind of bond where the electrons are transferred is called ionic bond. This bond occurs between a metallic and non-metallic elements. The other kind of bond (covalent) involves the sharing of electrons and this happens between non-metallic elements.

4 0
2 years ago
A car's bumper is designed to withstand a 6.84 km/h (1.9-m/s) collision with an immovable object without damage to the body of t
den301095 [7]

Answer:

F = 5.256 x 10^{3} N

Explanation:

From the work energy theorem we know that:

The net work done on a particle equals the change in the particles kinetic energy:

W = F.d, ΔK =\frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i}  , F.d = \frac{1}{2}mv^{2}_{f} -\frac{1}{2} mv^{2}_{i}

where:

W = work done by the force

F = Force

d = Distance travelled

m = Mass of the car

vf, vi = final and initial velocity of the car

kf, ki = final and initial kinetic energy of the car

Given the parameters;

m = 830kg

vi = 1.9 m/s

vf = 0 km/h

d = 0.285 m

Inserting the information we have:

F.d = \frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i}

F = \frac{\frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i} }{d}

F = \frac{ 0   - \frac{1}{2}  X830 X 1.9^{2} }{0.285}

F = 5.256 x 10^{3} N

3 0
3 years ago
A spring is stretched from equilibrium to 0.90 m and the work done on the spring equals 18j what is the value of the spring cons
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Work done is given by 1/2kx^2
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Why do astronomers use frequencies other than the visible ones when they are
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Because not all of the universe can be seen with a visible spectrum
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