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lapo4ka [179]
3 years ago
11

A 200.0 kg sled is being towed horizontally with a force of 25 N for 120 m in 30 seconds. What is the power of the applied force

?
Physics
1 answer:
Lesechka [4]3 years ago
3 0

Answer:

.

Explanation:

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A cat rides a merry-go-round while turning with uniform circular motion. At time t1 = 2.00 s, the cat's velocity is v with arrow
goldenfox [79]

Answer:

Part a)

a_c = 2.07 m/s^2

Part b)

a_{avg} = 1.32 m/s^2

Explanation:

As we know that it makes half revolution in given time interval

so we have

\frac{T}{2} = t_2 - t_1

\frac{T}{2} = 9 - 2

T = 14 s

now the angular speed is given as

\omega = \frac{2\pi}{T}

\omega = \frac{2\pi}{14}

\omega = 0.448 rad/s

now linear speed is given as

v = \sqrt{2.30^2 + 4.00^2}

v = 4.61 m/s

now we have

v = R \omega

4.61 = R(0.448)

R = 10.3 m

Now centripetal acceleration is given as

a_c = \omega^2 R

a_c = 0.448^2 \times 10.3

a_c = 2.07 m/s^2

Part b)

Average acceleration of the cat is given as

a_{avg} = \frac{v_2 - v_1}{\Delta t}

a_{avg} = \frac{2v}{\Delta t}

a_{avg} = \frac{2(4.61)}{9 - 2}

a_{avg} = 1.32 m/s^2

7 0
4 years ago
g When the movable mirror of the Michelson interferometer is moved a small distance X while making a measurement, 246 fringes ar
zhenek [66]

Answer:

X = 69.1 x 10⁻⁶ m = 69.1 μm

Explanation:

The relationship between the motion of the moveable mirror and the fringe count of the Michelson's Interferometer is given by the following formula:

d = mλ/2

where,

d = distance moved by the mirror = X = ?

m = No. of Fringes counted = 246

λ = wavelength of light entering interferometer = 562 nm = 5.62 x 10⁻⁷ m

Therefore,

X = (246)(5.62 x 10⁻⁷ m)/2

Therefore,

<u>X = 69.1 x 10⁻⁶ m = 69.1 μm</u>

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3 years ago
A physical property of gold is its
Irina18 [472]
Gold<span> is both malleable and ductile.</span>
8 0
3 years ago
What is the average velocity of a bowling ball that moves down the lane 8 meters in 4 seconds?​
Tema [17]

Answer: 2m/s

Explanation:

V avg = Displacement / time

Displacement is 8

Time is 4

V avg = 2

8 0
3 years ago
Buildings
Natasha2012 [34]

Buildings can affect the surface albedo.

The surface is the outermost or uppermost layer of a physical item or area. it is the element or place of the object which could first be perceived by an observer through the usage of the senses of sight and contact and is the component with which other materials first engage.

A surface is the outermost layer of any physical object. it is the part of the object that may be perceived by an observer using their experience of sight and touch and is the portion with which surrounding substances first engage.

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