Answer:
I will assume that “maximum force” implies the constant application of power P = 400 hp (international) to accelerating the vehicle. The force will therefore vary with speed as the vehicle accelerates. I will also assume that all engine energy goes into accelerating the vehicle, rather than rotating elements like its wheels.
In this case the 400 hp (equivalent to 298,280 watts) is applied for time t = 2 seconds. Therefore the kinetic energy of the vehicle is increased by:
ΔKE=Pt=(298,280)(2)=596,560 joules.
The initial kinetic energy is:
KEinitial=12mv2
=(0.5)(1600)(82)=51,200 joules.
Therefore final kinetic energy is:
KEfinal=KEinitial+ΔKE
=51,200+596,560
=647,760 joules
Therefore final vehicle velocity can be found:
KEfinal=12mv2
v=2KEfinalm−−−−−−−−√
=(2)(647,760)1600−−−−−−−−−−−√
= 28.455 m/s
Explanation:
Answer:
D) follows a circular path
Explanation:
This is because the magnetic force F on the charge, q due to the magnetic field B with velocity vector v perpendicular to it, equals the centripetal force acting on the charge.
So, F = Bqv = mv²/r.
So it follows a circular path.
1-Without gravity you can't grow any plant or tree because dirt would fly away
2-We are using gravity for a lot of physics system too
3-All the water on Earth would have been flying in the space
4-There wouldn't be atmosphere.
Answer:
a
b
The value is 
Explanation:
From the question we are told that
The mass is 
The spring constant is 
The instantaneous speed is 
The position consider is x = 0.750A meters from equilibrium point
Generally from the law of energy conservation we have that
The kinetic energy induced by the hammer = The energy stored in the spring
So
Here a is the amplitude of the subsequent oscillations
=> 
=> 
=>
Generally from the law of energy conservation we have that
The kinetic energy by the hammer = The energy stored in the spring at the point considered + The kinetic energy at the considered point
=> 
=>
If velocity is constants there is no acceleration therefore acceleration will equal zero.
