Question

A 20-cm long spring is attached to the wall. When pulled horizontally with a force of 100N, the spring stretches to a length of 22cm. What is the value of the constant? A.) The same spring is used in a tug of war. Two people pull on the ends, each with a force of 100N. How long is the stretched string? B.) The same spring is now suspended from a hook and a 10.2kg block is attached to the bottom end. How long is the stretched spring?

Answer 1

Answer:

Explanation:

Part 0

All the spring moves is 2 cm

x = 2 cm * [1 m / 100 cm ]

x = 0.020 meters

F = k*d

100N = k * 0.02 m

100 N / 0.02 = k

5000 N / m

Part A

The spring feels a force of 100 N - - 100N = 200 N because each person is pulling in the opposite direction.

F = k * x

200N = 5000 N/m * d

200 / 5000 = d

d = 0.04 meters.

Part B

10.2 kg must be converted to a force as experienced here on earth.

F = m * g

g = 9.81

m = 10.2

F = 10.2 * 9.81

F = 100.06 N

F = k * d

100.06 = 5000 * d

d = 100.06 / 5000

d = 0.02 meters.