The difference between the 6th term and the 9th term of the sequence is 135
<h3>How to determine the difference</h3>
Given that the nth term is;
3n² + 11
For the 6th term, the value of n is 6
Let's solve for the 6th term
= 3( 6)^2 + 11
= 3 × 36 + 11
= 108 + 11
= 119
For the 9th term, n = 9
= 3 (9)^2 + 11
= 3( 81) + 11
= 243 + 11
= 254
The difference between the 6th and 9th term
= 254 - 119
= 135
Thus, the difference between the 6th term and the 9th term of the sequence is 135
Learn more about algebraic expressions here:
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Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
Answer:
16d
Step-by-step explanation:
multiply 16 by d as there are 16 players for each team
Answer:
The answer is 36
Step-by-step explanation:
- First you have to divide 288 by 8 and
- then you have to see how many times 8 will go into 2 it can't so see how many times it will go into 28 which is 3 and you will get 24
- then you subtract 24 from 28 and you get 4
- then bring down the 8 an it 48 now see how many times 8 will go into 48 which is 6 times and you get 48
- then you subtract 48 by 48 and you get 0 so the answer is 36
- HOPE THIS HELPED
Answer:
-1/5x -4/5 = y
Step-by-step explanation:
f(x) = -5x -4
y = -5x-4
Switch x and y
x = -5y -4
Solve for y
Add 4
x+4 = -5y
Divide by -5
-1/5x - 4/5 = -5y/-5
-1/5x -4/5 = y
