Answer:
In order to evaluate the given expression 17(144) using the distributive property, Julia would rewrite the expression in friendlier numbers that is:
(10+7)(100+40+4)
Step-by-step explanation:
We are given an expression 17(144) that we have to evaluate let us say without using the calculator.
Sometimes, it is easier to solve a complex problem in multiple steps as the problem gets distributed and the difficulty level lowers for multiple smaller sets.
Julia would rewrite the expression as:
(10+7)(100+40+4)
Then solve it using distribution method as follows:
10(100+40+4)+7(100+40+4)
1000+400+40+700+280+28
= 2448
Answer: 7
Step-by-step explanation: whhhhyyyy
Answer: 4
Step-by-step explanation: I don't think you are in 1st grade but if you are here you go.
<h3>
Answer:</h3>
-y³ -6y²x +30
<h3>
Step-by-step explanation:</h3>
When parentheses are eliminated and the y variable placed first in each term, the expression simplifies to ...
... 15 -7y²x -y³ +y²x +15
Arranging like terms together, we have ...
... -y³ +y²x(-7 +1) +(15 +15)
... -y³ -6y²x +30
_____
The two different 3rd-degree terms can be expressed in either order. I have chosen to list the term with the largest exponent first. The expression could also be written with the same-degree terms in "lexicographical order", meaning the expression would be written ...
... -6xy² -y³ +30
