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2 years ago

An airplane accelerates from a velocity of 22 m/s to 40 m/s with an acceleration of 2 m/s2. How long does it

Physics

1 answer:

andrey2020 [161]2 years ago

4 0

The time it takes the plane to change its velocity is 9s.

Time can be defined the measured or measurable period during which an action, process, or condition exists or continues.

To calculate the time it takes the airplane to change its velocity, we use the formula below.

Formula:

t = (v-u)/a.......... Equation 1

Where:

a = Acceleration
v = Final velocity
u = Initial velocity
t = time

From the question,

v = 40 m/s
u = 22 m/s
a = 2 m/s²

Substitute these values into equation 1

t = (40-22)/2
t = 18/2
t = 9s

Hence, the time it takes the plane to change its velocity is 9s.

Learn more about time here: brainly.com/question/2854969

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2. Categorize each statement as true or false. A cylindrical capacitor is essentially a parallel-plate capacitor rolled into a t

Kruka [31]

Answer:

Explanation:

False --> A cylindrical capacitor is essentially a parallel plate capacitor rolled into a tube. This is because a cylindrical capacitor comprises two cylinders.

False --> The dielectric constant indicates the distance by which the two plates of a capacitor are separated.

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False --> The voltage across a capacitor in an RC circuit increases linearly during charging. This is because the voltage increases exponentially.

True --> One of the principal purposes of a capacitor is to store electric potential energy.

True --> A capacitor charges rapidly when connected to an RC circuit with a battery. This is because a cylindrical capacitor is basically a parallel plate capacitor rolled into a tube.

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3 years ago

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qwelly [4]

Answer:

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4 years ago

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Natasha_Volkova [10]

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2 years ago

A dragster travels 1/4 mi in 6.7 s. Assuming that acceleration is constant and the dragster is initially at rest, what is its ve

nlexa [21]

V0=0m/s (initially at rest)
t=6,7s
s=1/4mi=402,336m
s=(a*t^2)/2 -> a=2*s/t^2 -> a=2*402,336m/(6,7s)^2
a=804,672/44,89=17,93 m/s^2
<span>v=v0+at
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3 years ago

Read 2 more answers

E Describe the meaning of a line crossing the x-axis in a<br> velocity-time graph.

gizmo_the_mogwai [7]

Answer:

A line crossing the x-axis in a velocity-time graph means that the moving object has changed its direction.

Explanation:

Velocity-Time graph:

A velocity-time graph is a two dimensional graph with velocity at its y-axis and time at its x-axis. At any point, value of y represents the velocity and value of x represents the time. The slope of the graph gives us the acceleration or deceleration of the moving object.

In a velocity-time graph:

- A straight line represents constant velocity.

- A diagonal line means that the velocity of a body is changing.

*Referring to the figure attached with the answer*

The velocity of the moving object increases at a constant rate for the first 10 minutes. Then the velocity is 60 m/min for the next 5 minutes. After that the velocity is decreasing. Till 30th minute when the velocity is at 0 m/min.

What happens here?

Velocity is a vector quantity. It has some direction. In a velocity-time graph, we are only concerned with two directions of velocity:

- Forward direction

- Backward direction

So, the object stops at 30th minute and starts moving in the reverse direction after that with an increasing velocity. <u>The point where the line cuts the x-axis is basically the point where the object starts moving in the reverse direction.</u>

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3 years ago